<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-5129052553947207130</id><updated>2011-04-21T11:14:02.051-07:00</updated><title type='text'>Leaving Cert Maths</title><subtitle type='html'>This blog is intended for my Leaving Cert Maths class - who are taking ordinary level maths.
If the information here is of use to anyone else, you are welcome to view it for your personal use.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>54</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7071257341811802061</id><published>2009-02-13T10:27:00.000-08:00</published><updated>2009-02-18T12:57:23.230-08:00</updated><title type='text'>Revision questions for the Mid-term break</title><content type='html'>&lt;span&gt;These are the questions you should try to work through over the mid-term break.&lt;/span&gt;&lt;span style="font-weight: bold;"&gt; &lt;/span&gt;&lt;span&gt;Attempt as much of it as you can after revising the related chapters.&lt;br /&gt;If you get stuck, check here over the course of next week, as I may post some tips for each section.&lt;br /&gt;In the classes after the mid-term break, we will cover as much ground as possible and hopefully resolve any issues that you got stuck on.&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;&lt;br /&gt;&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;I will add some help in blue text like this for some of the questions over the next few days.&lt;br /&gt;I have now finished adding my notes - you can add a comment here if you need more help.&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Paper 1&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;Question 1 - Arithmetic&lt;/span&gt;&lt;br /&gt;Page 135 q4, 5 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(In q4b, put all money amounts into either euro or cent.In q4c, remember the way we laid out these questions - you need to navigate backwards from the net tax, adding pack tax credits etc.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 2,3 - Algebra&lt;/span&gt;&lt;br /&gt;Page 22 q2 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(In part b and c you should tidy up the equations with fractions by multiplying across by the number under the line. In the evaluation questions, write on the page e.g. 2(-2)² - 3(-2)(1/3) before you go to your calculator.&lt;/span&gt;&lt;br /&gt;Page 40 q6 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(part a: find LCM of the denominators. Part b: remember that (x-2)² = (x-2)(x-2). Part c: remember that if say x=2 is a root of the equation, it means that if you sub x=2 in to the equation it will balance. There will be only 1 unknown which you can solve.)&lt;/span&gt;&lt;br /&gt;Page 156 q3, 7 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(Part b: Use the rules on page 140 to work out how to write 1/27 as 3 to the power of something. A clue is that 3³=27. Also note that 3²=9. Write both sides of the equation as 3 to the power of something and then equate the powers.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 4 - Complex Numbers&lt;/span&gt;&lt;br /&gt;Page 78 q6 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(For all these questions, you need to revise argand diagrams, complex conjugates, modulus and division of complex numbers. For part b see the top of page 76 for a similar question.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 6,7,8 - Functions and Calculus&lt;/span&gt;&lt;br /&gt;Page 281 q 6 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(For part bi) the coordinates of a and b are both going to be (something, 0) as they are both on the x-axis, or y = 0. So if you solve the equation  x² +2x -3 = 0 you will get the two values of x. c is on the Y-axis, so this means that x=0. Sub this value of x in to x² +2x -3 and you will get the output value y. Part iii is like a repeat of part i with =0 replaced by = -3. Remember that you can only solve quadratic equations with = 0 on the right hand side so you need to rearrange it before solving.)&lt;/span&gt;&lt;br /&gt;Page 306 q2, 4 and 5(a) &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(For q2, you need to use the quotient rule for ii and iii. In iii you can write as a single fraction, but you can't simplify the top of the fraction. First principles is coming up on the mock exam, worth 20 marks, so practice a few of these. Make sure you always check your answer f(x) =x² -4x so f'(x) = 2x -4. For part c, you need to get the 1st derivative and set up an equation with this = 2. Note you are asked for the point on the curve, so this means you have to give an (x,y) pair and you can find y by subbing x into the original function. Turning point occurs where slope = 0, check your notes on the shape of a function (wine-glass upsidedown or right way up) to work out if it is a max or a min.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Paper 2 &lt;/span&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 1 - Perimeter area and volume&lt;/span&gt;&lt;br /&gt;Page 175 q14&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt; (Remember the relationship between the radius, the height and the slant height of a cone - a right angle triangle. For the last part of the question, you need to set up an equation: vol of cylinder = 5 × vol of cone. Leave both volumes in terms of π.)&lt;/span&gt;&lt;br /&gt;Page 184 q5, page 185 q7 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(Straightforward Simpson's Rule questions, the second one has an unknown as one of the heights.)&lt;/span&gt;&lt;br /&gt;Page 189 q5&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt; (Part b works out exactly if you use π = 22/7)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 2 and 3 - Coordinate Geometry of Line and Circle&lt;/span&gt;&lt;br /&gt;Page 58 q5, 13 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(For q5: remember that the corners of a parallelogram are always given either clockwise or anti-clockwise in order. Try drawing a rough sketch and solve using translations. For q 13 you check if a point is on a line by subbing. The word "verify" means that the point&lt;/span&gt;&lt;span style="font-weight: bold; font-style: italic; color: rgb(51, 51, 255);"&gt; is&lt;/span&gt;&lt;span style="color: rgb(51, 51, 255);"&gt; on the line.&lt;/span&gt;&lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt; To find the equation of the image of a line you have to find the two points on the line, find the slope&lt;span style="color: rgb(255, 0, 0);"&gt; (*) &lt;/span&gt;and plug values into y -y1 = m(x - x1). &lt;span style="color: rgb(255, 0, 0);"&gt;&lt;br /&gt;(*) &lt;/span&gt;Note that the slope won't change under translation so that step isn't necessary.)&lt;/span&gt;&lt;br /&gt;Page 61 q1&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt; (Remember how to calculate the slopes of perpendicular lines - invert and change sign. For part c, find the distance between a and b. Then set up an equation with the distance formula subbed in for a(1,6) and c(2,y) on the left hand side and the distance between a and b on the right hand side. To solve this equation, your first step will be to square both sides before re-arranging it as ...x² ...x....a number =0 and solving.)&lt;/span&gt;&lt;br /&gt;Page 208 q3 &lt;span style="font-style: italic; color: rgb(51, 51, 255);"&gt;(Very straightforward circles question if you revise the chapter. You prove if a point is on a circle exactly the same way that you prove a point is on a line - by subbing in (x,y).) To prove the last part, you need to find the equation of the line that the 2 points (centres of the circles) are on .... slope, y-y1= m(x-x1) etc.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 6 - Probability&lt;/span&gt;&lt;br /&gt;Page 239 q2 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(Revise the notation. Large brackets with e.g. 5 on top and 2 below means "5 choose 2" - in other words how many ways can you choose 2 people from a group of 5. The answer is (5×4)/(2×1) and you can work this out using the nCr button on your calculator.)&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;Page 256 q6 (Part b could be solved with a sample space B1 B2 G1 G2. If you write the sample space correctly (should have 24 rows) then you can just count the number of cases where the 2 girls are in the middle and express P(2 girls in middle)=this number/24. For part c, this is like the one we did in class. If the number has to be bigger than 9000 then there is only 1 option for the first position, 4 left for the second position etc. If the number must be even then there are 3 options for the last position. Remember to always start with the most restricted positions.)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 7 - Statistics&lt;/span&gt;&lt;br /&gt;Page 105 q2&lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt; (Note the means are different, but the two sets of data are equally "spread out". Make a table with the values in the first column, the difference between it and the mean in the next column, this value squared next and so on. Follow the steps on the previous page.)&lt;/span&gt;&lt;br /&gt;Page 110 q7 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(For the median, you have to imagine the data written out long (i.e. not in a frequency distribution. It would be 2 2 2 3 3 3 3 5 6 6  and the median value would be the middle value. When drawing the ogive in part b, be sure to put the frequency (i.e. number of students) on the vertical axis. If there are 40 students, then the last entry in the cumulative frequency table should be 40. The median student will be the 20th student, lower quartile will be the 10th student and upper quartile will be the 30th student. Find these students on the vertical axis and then draw lines across to your curve and down to read the corresponding marks on the horizontal axis. Remember the interquartile range is a number (not an upper and lower number as in the range of a periodic function.)) &lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Question 11 - Linear Programming&lt;/span&gt;&lt;br /&gt;Page 396 q3, 6 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(For both of these, use points to find slope, then use slope and one point to find equation of the line, then use a test point to decide the direction of the inequality).&lt;/span&gt;&lt;br /&gt;Page 414 q6 &lt;span style="color: rgb(51, 51, 255); font-style: italic;"&gt;(For part b, your first inequality has to do with "number of people the chalet types can accomodate. Don't forget that x is the number of type A that the builder is going to build - so if he builds 10 of them then they can accommodate 6x or 6%times;10 = 60 people. When graphing don't forget to shade in the appropriate region, taking the two implicit inequalities x ≥ 0 and y ≥0 into account. For part ii, you need to work out the intersection point of the two diagonal lines on your graph using simultaneous equations and then maximise the expression you create using the additional information you're given about rent.)&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7071257341811802061?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7071257341811802061/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7071257341811802061' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7071257341811802061'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7071257341811802061'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2009/02/revision-questions-for-mid-term-break.html' title='Revision questions for the Mid-term break'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4696712188091919645</id><published>2009-02-12T12:00:00.000-08:00</published><updated>2009-02-12T12:24:51.233-08:00</updated><title type='text'>Statistics question</title><content type='html'>P 111 q 8.&lt;br /&gt;&lt;br /&gt;(a) This table is a frequency distribution and the second row in tables like this is always the frequency. &lt;br /&gt;You can either be asked to find the mean in which case you multiply each number in the top row by its frequency and add these together and then divide by the sum of the frequencies.&lt;br /&gt;In this case you are given the mean, so, kind of like the simpsons rule example we did today, you set up an equation and solve it.&lt;br /&gt;Left hand side of equation:&lt;br /&gt;You will have 0(1) + 1(x) + etc on top and 1 + x + 1 etc on the bottom.&lt;br /&gt;Right hand side of equation: &lt;br /&gt;This will be the mean which you have been given.&lt;br /&gt;Then you will have an equation with a fraction in it, so you multiply across by whatever is under the line and solve.&lt;br /&gt;&lt;br /&gt;(b) See page 103.&lt;br /&gt;The standard deviation is a measure of how spread out data is.&lt;br /&gt;You could have 2 sets of numbers with the same mean eg&lt;br /&gt;1 2 3 4 5 6 7 8 9 10    &lt;br /&gt;and&lt;br /&gt;5 5 5 5 5 6 6 6 6 6 &lt;br /&gt;both have mean = 5.5, but the standard deviation of the first set would be bigger because the numbers are more spread out.&lt;br /&gt;To find standard deviation you need to first find the mean value and then make a little table:&lt;br /&gt;First column is all the numbers in your list.&lt;br /&gt;Second column is the difference between the number in the 1st column and the mean.&lt;br /&gt;Third column is the number in the 2nd column squared.&lt;br /&gt;Add the values of the third column.&lt;br /&gt;Then divide this number by the number of values.&lt;br /&gt;Then get the square root of the result.&lt;br /&gt;When you have done this take a look at how to find the standard deviation of a frequency distribution.&lt;br /&gt;&lt;br /&gt;(c) This is explained on page 96.&lt;br /&gt;When you are making the cumulative frequency table, note that the last number should be 240 (as you are told there are 240 villagers).&lt;br /&gt;When drawing the ogive, make sure that you put the frequency (which is no. of villagers) on the vertical axis. On the horizontal axis you put the values you have in the top row, without the &amp;le; or &amp;lt; signs. &lt;br /&gt;You graph cumulative frequencies on an ogive.&lt;br /&gt;(i) For the median, you need to find the "middle" villager. Start on the vertical axis.&lt;br /&gt;(ii) The interquartile range is found by finding the difference between the ages of the lower quartile villager and the upper quartile villager.&lt;br /&gt;For both these questions you start on the vertical axis, draw a horizontal line until it reaches the curve, then drop a vertical line to read the age from the horizontal axis.&lt;br /&gt;(iii) For this question, you need to start on the age axis at 55. Then go up to the curve and then across to the vertical axis. Then re-read what the question is asking you.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4696712188091919645?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4696712188091919645/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4696712188091919645' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4696712188091919645'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4696712188091919645'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2009/02/statistics-question.html' title='Statistics question'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-8278256001770116356</id><published>2009-02-10T11:19:00.000-08:00</published><updated>2009-02-10T11:36:54.958-08:00</updated><title type='text'>Probability question</title><content type='html'>This is some help for q1 on page 254.&lt;br /&gt;&lt;br /&gt;(a) Use the same approach as we used today for "roll a die - what is the probability of getting a 4?" type of question. There are 6 sides, one of them is a 4 so the probability P(4) = 1/6.&lt;br /&gt;If you were asked for the probability of getting a 4 or a 3, then it would be P(4or3)= 2/6 = 1/3&lt;br /&gt;&lt;br /&gt;(b) Arrangements. There are 6 letters, so there are 6 options for the first position, 5 for the second and so on.&lt;br /&gt;If the first position must contain B, then there is 1 option for that position, 5 for the second and so on.&lt;br /&gt;For the third part of this question, there are further restrictions. Start with the most restricted positions and then work out how many options remain for the other positions.&lt;br /&gt;&lt;br /&gt;(c) Similar to the arrangements questions, but with a bit of extra logic required.&lt;br /&gt;For part (iii) remember that there are only 4 digit positions to be filled, so there are 6 options for the first position, 5 for the next, 4 for the next and 3 for the last.&lt;br /&gt;For part (iv) if the number is to be &amp;gt;4000 then the first digit must be either 4 or 5 - in other words there are only 2 options.&lt;br /&gt;&lt;br /&gt;We won't get much more of a chance to revise probability so look over the whole chapter 11 now.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-8278256001770116356?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/8278256001770116356/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=8278256001770116356' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8278256001770116356'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8278256001770116356'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2009/02/probability-question.html' title='Probability question'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-785352530147620443</id><published>2009-02-09T11:18:00.000-08:00</published><updated>2009-02-09T12:25:16.889-08:00</updated><title type='text'>Complex Numbers Question</title><content type='html'>To do question 4 on page 78 you need&lt;br /&gt;&lt;br /&gt;(a) to be able to draw an Argand Diagram (see page 72) and to plot the complex numbers&lt;br /&gt;z = 1-4i  and iz = i(1-4i) on it.&lt;br /&gt;Before you plot the second number you have to multiply out i(1-4i). This works the same way as multiplying say, x(1+4x) would in algebra, but there is a second step you need to do - resolving the i&amp;sup2;=-1&lt;br /&gt;&lt;br /&gt;(b) To do this you need to remember division of complex numbers (page 68).&lt;br /&gt;10-2i&lt;br /&gt;------&lt;br /&gt;2-3i&lt;br /&gt;You multiply above and below by the complex conjugate of the bottom.&lt;br /&gt;[If z = 1 + 7i, then z&amp;macr;, the complex conjugate of z = 1-7i]&lt;br /&gt;So you multiply above and below by (2+3i)&lt;br /&gt;(10-2i)(2+3i)&lt;br /&gt;-------------&lt;br /&gt;(2-3i)(2+3i)&lt;br /&gt;If you don't get a real number below (after you have adjusted i&amp;sup2;=-1) then you've made a mistake.&lt;br /&gt;Whatever you get for your result, you have to factor out (1+i) in order to find the missing value k. If you don't get something like 2+2i which could be written as 2(1+i) or 3+3i which could be written as 3(1+i) then you have made a mistake.&lt;br /&gt;Note also that they say k&amp;isin;N which is a further clue - telling you that it is positive and not a fraction.&lt;br /&gt;(c)&lt;br /&gt;(i) for this you need to revise equality of complex numbers (p70).&lt;br /&gt;If you are told 2a + 2i = 6 +bi then you can equate the real parts of the equation&lt;br /&gt;2a = 6 so a = 3&lt;br /&gt;and the imaginary parts&lt;br /&gt;2 = b &lt;span style="font-weight:bold;"&gt;(Note - leave the i's out of the imaginary equation)&lt;/span&gt;&lt;br /&gt;to solve.&lt;br /&gt;Sub in w = 3-4i and solve.&lt;br /&gt;(ii) ¦w¦ is the modulus of w (page 73).&lt;br /&gt;Sub in all the values you are given, and solve the real and imaginary equations using the same rules as above (equate the reals, equate the imaginary parts).&lt;br /&gt;In this case, the solution is much more complicated. You end up with s's and t's in both equations, so you have to solve using simultaneous equations.&lt;br /&gt;The answers turn out to be fractions which look a bit unlikely - but again there is a clue in the question where you are told s,t &amp;isin; R.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-785352530147620443?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/785352530147620443/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=785352530147620443' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/785352530147620443'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/785352530147620443'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2009/02/complex-numbers-question.html' title='Complex Numbers Question'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7543392056728550587</id><published>2009-02-08T13:03:00.000-08:00</published><updated>2009-02-08T13:10:12.906-08:00</updated><title type='text'>Lead up to Mock Exams</title><content type='html'>As preparation for the mock exams, we will revise the following topics in this order.&lt;br /&gt;Monday 9:&lt;br /&gt;Coordinate geometry of the line and circle&lt;br /&gt;&lt;br /&gt;Tuesday 10:&lt;br /&gt;Complex Numbers&lt;br /&gt;&lt;br /&gt;Wednesday 11:&lt;br /&gt;Probability&lt;br /&gt;&lt;br /&gt;Thursday 12:&lt;br /&gt;Perimeter area and volume&lt;br /&gt;&lt;br /&gt;Friday 13:&lt;br /&gt;Statistics&lt;br /&gt;&lt;br /&gt;Over the mid-term break, I will set some work to do covering algebra and revising functions.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7543392056728550587?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7543392056728550587/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7543392056728550587' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7543392056728550587'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7543392056728550587'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2009/02/lead-up-to-mock-exams.html' title='Lead up to Mock Exams'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2192513148004666846</id><published>2008-05-26T11:58:00.000-07:00</published><updated>2008-06-06T15:23:43.678-07:00</updated><title type='text'>Paper 2 Question 11 - Linear Programming</title><content type='html'>Here are the notes on Linear Programming:&lt;br /&gt;&lt;br /&gt;Introduction - &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/linear-programming.html"&gt;here &lt;/a&gt;and &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/linear-programming.html"&gt;here &lt;/a&gt;&lt;br /&gt;Looking at &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/half-plane-is-region-on-co-ordinated.html"&gt;part a) half-planes &lt;/a&gt;&lt;br /&gt;Worked example of a&lt;a href="http://leavingcertmaths.blogspot.com/2008/04/linear-programming-part-b.html"&gt; part b).&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;NB: when answering part b) (i) which is usually "write down two inequalities in x and y and illustrate these on graph paper" you must&lt;br /&gt;a) use graph paper and&lt;br /&gt;b) &lt;span style="font-weight: bold;"&gt;shade in the region&lt;/span&gt; which represents all the inequalities (including x&amp;ge;0 and y&amp;ge;0) or at least &lt;span style="font-weight: bold;"&gt;indicate the half planes&lt;/span&gt; with arrows. If you just draw the lines you could lose 3 marks per inequality ... or 1%!&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2192513148004666846?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2192513148004666846/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2192513148004666846' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2192513148004666846'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2192513148004666846'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-11-linear-programming.html' title='Paper 2 Question 11 - Linear Programming'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6811732652130826504</id><published>2008-05-26T11:55:00.000-07:00</published><updated>2008-05-26T11:58:42.101-07:00</updated><title type='text'>Paper 2 Question 7 - Statistics</title><content type='html'>Here are the links to the statistics notes on this blog.&lt;br /&gt;&lt;br /&gt;Introduction - &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/leaving-cert-statistics.html"&gt;here&lt;/a&gt;&lt;br /&gt;A follow up with notes on an exam question - &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/statistics-wrap-up.html"&gt;here&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6811732652130826504?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6811732652130826504/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6811732652130826504' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6811732652130826504'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6811732652130826504'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-7-statistics.html' title='Paper 2 Question 7 - Statistics'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6936393662580347970</id><published>2008-05-26T11:51:00.000-07:00</published><updated>2008-05-26T11:55:29.216-07:00</updated><title type='text'>Paper 2 Question 6 - Probability</title><content type='html'>Here are the links to notes on Probability:&lt;br /&gt;&lt;br /&gt;&lt;a href="http://leavingcertmaths.blogspot.com/2008/05/probability-question.html"&gt;A Tricky probability question done using rules of probability and sample space technique.&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6936393662580347970?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6936393662580347970/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6936393662580347970' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6936393662580347970'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6936393662580347970'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-6-probability.html' title='Paper 2 Question 6 - Probability'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6203871281034198221</id><published>2008-05-26T11:49:00.000-07:00</published><updated>2008-06-06T15:31:58.588-07:00</updated><title type='text'>Paper 2 Question 5 - Trigonometry</title><content type='html'>Here are the links to Trigonometry&lt;br /&gt;The main points you need to know to cover 90% or questions asked in exams are listed &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/trigonometry.html"&gt;here&lt;/a&gt;.&lt;br /&gt;A one-page overview and a subtlety of finding the inverse Sine of an angle &gt; 90&amp;deg; is &lt;a href="http://http://leavingcertmaths.blogspot.com/2008/04/more-trigonometry.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6203871281034198221?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6203871281034198221/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6203871281034198221' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6203871281034198221'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6203871281034198221'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-5-trigonometry.html' title='Paper 2 Question 5 - Trigonometry'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-1996649119142971403</id><published>2008-05-26T11:47:00.000-07:00</published><updated>2008-06-06T15:28:35.672-07:00</updated><title type='text'>Paper 2 Question 2 and 3 - Co-ordinate Geometry of the Line and Circle</title><content type='html'>Here are the links related to Co-ordinate Geometry of the Line and Circle.&lt;br /&gt;&lt;br /&gt;A one-page overview of the topic &lt;a href="http://leavingcertmaths.blogspot.com/2008/03/co-ordinate-geometry.html"&gt;here&lt;/a&gt;.&lt;br /&gt;The key points you need to know for coordinate geometry of the circle &lt;a href="http://leavingcertmaths.blogspot.com/2008/03/one-last-day-on-co-ordinate-geometry.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-1996649119142971403?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/1996649119142971403/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=1996649119142971403' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1996649119142971403'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1996649119142971403'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-2-and-3-co-ordinate.html' title='Paper 2 Question 2 and 3 - Co-ordinate Geometry of the Line and Circle'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-8989290743089560775</id><published>2008-05-26T11:45:00.000-07:00</published><updated>2008-06-06T15:26:24.082-07:00</updated><title type='text'>Paper 2 Question 1 - Perimeter Area and Volume</title><content type='html'>These links are related to Perimeter, Area and Volume.&lt;br /&gt;An overview &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/perimeter-area-volume.html"&gt;here&lt;/a&gt;&lt;br /&gt;Lots of examples of how to tackle different types of Simpson's rule questions &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/simpsons-rule.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-8989290743089560775?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/8989290743089560775/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=8989290743089560775' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8989290743089560775'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8989290743089560775'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-2-question-1-perimeter-area-and.html' title='Paper 2 Question 1 - Perimeter Area and Volume'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-3702122327198691579</id><published>2008-05-26T11:42:00.001-07:00</published><updated>2008-06-04T12:56:21.422-07:00</updated><title type='text'>Paper 1 Question 6, 7 and 8 - Functions and Differentiation</title><content type='html'>Here are the links relating to Functions and Differentiation:&lt;br /&gt;&lt;br /&gt;An overview of functions and graphs &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/functions-and-graphs.html"&gt;here&lt;/a&gt;.&lt;br /&gt;Some notes on differentiating from first principles &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/differentiating-from-first-principles.html"&gt;here&lt;/a&gt;.&lt;br /&gt;Some notes on how you lose marks when differentiating from first principles &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/differentiation-test.html"&gt;here&lt;/a&gt;.&lt;br /&gt;One page overview of differentiation &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/finishing-up-differentiation.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-3702122327198691579?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/3702122327198691579/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=3702122327198691579' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3702122327198691579'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3702122327198691579'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-1-question-6-7-and-8-functions.html' title='Paper 1 Question 6, 7 and 8 - Functions and Differentiation'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-3363415510009489319</id><published>2008-05-26T11:40:00.000-07:00</published><updated>2008-06-04T12:52:25.353-07:00</updated><title type='text'>Paper 1 Question 4 - Complex Numbers</title><content type='html'>This is the only blog entry on complex numbers. It gives the &lt;a href="http://leavingcertmaths.blogspot.com/2008/03/complex-numbers.html"&gt;1-page overview.&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-3363415510009489319?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/3363415510009489319/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=3363415510009489319' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3363415510009489319'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3363415510009489319'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-1-question-4-complex-numbers.html' title='Paper 1 Question 4 - Complex Numbers'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-3262166451198593845</id><published>2008-05-26T11:38:00.000-07:00</published><updated>2008-06-04T12:40:04.015-07:00</updated><title type='text'>Paper 1 Question 2 and 3 - Algebra</title><content type='html'>Here are all the links to algebra entries on this blog.&lt;br /&gt;&lt;br /&gt;There is an overview of algebra &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/leaving-cert-algebra.html"&gt;here&lt;/a&gt;.&lt;br /&gt;An example of simultaneous equations one linear one quadratic and awkward algebraic fractions can be found &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/alegbra-class.html"&gt;here&lt;/a&gt;. (sorry about the formatting in the second part, if anyone can tell me why " " doesn't work, I'm all ears).&lt;br /&gt;There are some notes on numberlines and manipulating indices &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/algebra.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-3262166451198593845?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/3262166451198593845/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=3262166451198593845' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3262166451198593845'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3262166451198593845'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-1-question-2-and-3-algebra.html' title='Paper 1 Question 2 and 3 - Algebra'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4406049474119991308</id><published>2008-05-26T11:35:00.000-07:00</published><updated>2008-06-04T12:18:25.623-07:00</updated><title type='text'>Paper 1 Question 1 Arithmetic</title><content type='html'>Here are the links to arithmetic to help you revise for this question:&lt;br /&gt;&lt;br /&gt;There is an overview of the arithmetic question and in particular compound interest &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/arithmetic.html"&gt;here&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4406049474119991308?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4406049474119991308/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4406049474119991308' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4406049474119991308'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4406049474119991308'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-1-question-1-arithmetic.html' title='Paper 1 Question 1 Arithmetic'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7611673951751762804</id><published>2008-05-20T11:41:00.001-07:00</published><updated>2008-05-20T11:43:35.373-07:00</updated><title type='text'>Linear Programming Class - Thursday morning</title><content type='html'>There will be a special Linear Programming class on Thursday (22nd May) morning for anyone who is interested. The class will be in Room 1 at 8:40 (normal maths class time).&lt;br /&gt;If you would like a class focussing on another topic, or just want to have a meeting with me, contact me at the school asap.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7611673951751762804?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7611673951751762804/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7611673951751762804' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7611673951751762804'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7611673951751762804'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/linear-programming-class-thursday.html' title='Linear Programming Class - Thursday morning'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7281024260787765488</id><published>2008-05-14T12:33:00.000-07:00</published><updated>2008-05-14T12:34:43.046-07:00</updated><title type='text'>Checklist for exam</title><content type='html'>&lt;table border="0" cellspacing="0" cols="1" frame="void" rules="none"&gt;  &lt;colgroup&gt;&lt;col width="512"&gt;&lt;/colgroup&gt;  &lt;tbody&gt;   &lt;tr&gt;    &lt;td align="left" height="36" valign="top" width="512"&gt;Make sure you have your exam strategy ready long before the exam. Be familiar with which questions you are planning to answer. &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="36" valign="top"&gt;Have your pens, pencil, calculator (check battery), geometry set ready well before the exam time.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="87" valign="top"&gt;2½ hours for exam = 25 mins per question. Exam starts at 9:30, you should be well into your 2nd question by 10am. If you have choices, do not spend too long deciding which questions you are going to do. Circle the questions you are going to do and draw a pencil line through the questions you are definitely not going to attempt.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="36" valign="top"&gt;Write clearly. Number all questions and parts of questions. Don't waste time rewriting the question. Highlight your answer clearly.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="53" valign="top"&gt;Keep all parts of each question together. It is a good idea to keep questions in order. If you have to come back to re-attempt a question later in the exam, it will be easier to find it. &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="70" valign="top"&gt;Read questions carefully, do your work and then read question again to make sure you have done what was asked and to make sure you format your answer properly (correct to 2 decimal places, as a fraction, in surd form, in km/h etc.).&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="70" valign="top"&gt;Attempt all questions. Where there is a part (i), (ii), (iii) etc., don't assume that if you cannot finish part (i) that you cannot attempt part (ii), (iii). If you are running out of time remember how to get attempt marks - “any correct substitution”.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;Only attempt a 7th question after you have checked the first 6.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="36" valign="top"&gt;Some students find it reassuring to write all the formulae you have memorised down as soon as you are told that you may start.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="left" height="19" valign="top"&gt;Remember, for every blunder (-3 marks) you lose ½%, so be careful!&lt;/td&gt;   &lt;/tr&gt;  &lt;/tbody&gt; &lt;/table&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7281024260787765488?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7281024260787765488/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7281024260787765488' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7281024260787765488'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7281024260787765488'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/checklist-for-exam.html' title='Checklist for exam'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-8748413971199063882</id><published>2008-05-14T12:31:00.001-07:00</published><updated>2008-05-14T12:33:12.751-07:00</updated><title type='text'>How NOT to lose marks in your LC exam</title><content type='html'>&lt;table border="0" cellspacing="0" cols="5" frame="void" rules="none"&gt;  &lt;colgroup&gt;&lt;col width="159"&gt;&lt;col width="23"&gt;&lt;col width="397"&gt;&lt;col width="23"&gt;&lt;col width="336"&gt;&lt;/colgroup&gt;  &lt;tbody&gt;   &lt;tr&gt;    &lt;td align="right" height="27" valign="top" width="159"&gt;&lt;b&gt;&lt;span style="font-size:130%;"&gt;Question&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top" width="23"&gt;&lt;b&gt;&lt;span style="font-size:130%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="left" valign="top" width="397"&gt;&lt;b&gt;&lt;span style="font-size:130%;"&gt;How I lose marks ...&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top" width="23"&gt;&lt;b&gt;&lt;span style="font-size:130%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="left" valign="top" width="336"&gt;&lt;b&gt;&lt;span style="font-size:130%;"&gt;How I get them back.&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Arithmetic&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not giving answer in correct format.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Recheck what was asked.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not handling percentages, percentage error and taxes properly.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice all type of percentage questions&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Algebra&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to square an expression properly (x+y)² = x² + y² + 2xy&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Getting sloppy towards the end of a simplification, mixing up signs, adding instead of multiplying....&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice and be careful. Then, substitute test values to verify results.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to find corresponding y-values after solving for x, esp when one simultaneous equation is quadratic.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Pay attention to steps of solution – always include the checking answers step.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not handling laws of indices properly&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Learn these – check them on your calculator! Make sure you can enter complicated indices on your calculator correctly.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Complex numbers&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to set i² = -1&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not recognising symbols and their meanings: complex conjugate z-bar, modulus |2+3i| &lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Go over chapter – it is quite self-contained.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not handling substitution properly w=2+3i, what is w²&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Look at past exam questions.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not knowing quadratic formula properly&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Write it down and check it every day.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;Functions&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not showing marks on graph or understanding how to use graph,&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Use a pencil and ruler to show how you interpret graph.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Uneven scale on x- or y-axis&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Use graph paper, watch that all intervals are even, including 0 to 1, 1 to 2 etc.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;Differentiation&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not taking care applying rules for differentiation, or not knowing chain rule (it is not in tables)&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Learn it and practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Leaving out LHS or Limit idea in first principles.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;Perimeter, area &amp;amp; volume&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not knowing simpson's rule inside out.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice, especially with unknown heights etc.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="20" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not handling Π as requested.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Re-check what you are asked.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;General errors applying formulae.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice using tables for formulae, and sanity check your answers.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="50" valign="top"&gt;&lt;b&gt;Co-ordinate geometry of line&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not knowing formulae and how to apply them.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;As for quadratic formula, write them out each day – make sure you understand logic of slope, midpoint and distance formulae.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Uneven scale on x- and y-axis (must be both to same scale)&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Use graph paper and check this.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="50" valign="top"&gt;&lt;b&gt;Co-ordinate geometry of circle&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not taking minus signs into account in formula for equation of circle (e.g. (x-2)² + (y+3)² = 8 means centre of circle is (2,-3) and radius = √8&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="50" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to understand geometry of circle (tangent at a point perpendicular to radius, tangents at opp end of diameter are parallel)&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Go over JC geometry if necessary.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Trigonometry&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not knowing or correctly using Sin= 0pp/Hyp etc&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Learn mnemonic.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to “fill out” the sine rule/ cosine rule correctly.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Being caught out by inverse sine of an angle that is &gt;90º&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Be alert. &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Having calculator set to radians or not knowing how to use degrees/minutes function.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Check it and practice.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;Probability&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not showing your work&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Can be difficult, but write something in case your answer is wrong.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Failing to see that there are two ways a combined event can happen and adding probabilities of each.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Use a sample space to check answers&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Statistics&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Forgetting to divide by sum of frequencies&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Sanity check answers&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not showing marks on graph (eg median from ogive)&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Indicate how you use graph clearly&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="top"&gt;&lt;b&gt;Linear programming&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not indicating half-plane when graphing inequalities&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Include it in your graph.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Leaving out the “obvious” inequalities, x≥0&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Make sure you give the number of inequalities you were asked for.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not using simultaneous equations to calculate point of intersection.&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;You must not use your graph for this part.&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td align="right" height="34" valign="top"&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▼&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Not writing english sentence at the end&lt;/td&gt;    &lt;td align="right" valign="top"&gt;▲&lt;/td&gt;    &lt;td align="left" valign="top"&gt;Explain what x=10, y=7 means, 10 what, 7 what and why (“to maximise profit” or whatever).&lt;/td&gt;   &lt;/tr&gt;  &lt;/tbody&gt; &lt;/table&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-8748413971199063882?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/8748413971199063882/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=8748413971199063882' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8748413971199063882'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8748413971199063882'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/how-not-to-lose-marks-in-your-lc-exam.html' title='How NOT to lose marks in your LC exam'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-64142265493489969</id><published>2008-05-11T12:18:00.000-07:00</published><updated>2008-11-12T21:09:24.259-08:00</updated><title type='text'>Probability Question</title><content type='html'>While the probability question can be very straightforward, you need to pay attention to the detail of what you are being asked. I gave this question (1999) in the mini-mock exam and nobody got it right.&lt;br /&gt;&lt;br /&gt;In your exam, you can answer questions like this using the sum or product of probabilities as appropriate or using a sample space. While the sample space might take some time to set up, it is a foolproof method. To illustrate how the probabilities work, I have created the matching sample space for each part of the question.&lt;span style="text-decoration: underline;"&gt; (you will need to click on the image to be able to read the text within the sample space diagram)&lt;br /&gt;&lt;/span&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/SCdKcG0h8rI/AAAAAAAAAE8/hf8s80stYR8/s1600-h/1999prob.jpg"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/SCdKcG0h8rI/AAAAAAAAAE8/hf8s80stYR8/s400/1999prob.jpg" alt="" id="BLOGGER_PHOTO_ID_5199206141550260914" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Note that there are 66 possible combinations, as you cant pick the same exact sample twice and selecting e.g. A1 and B2 is the same as selecting B2 and A1.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Looking at part (i):&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SCdLQW0h8sI/AAAAAAAAAFE/cRPIjx0UjM0/s1600-h/1999probpart1.jpg"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SCdLQW0h8sI/AAAAAAAAAFE/cRPIjx0UjM0/s400/1999probpart1.jpg" alt="" id="BLOGGER_PHOTO_ID_5199207039198425794" border="0" /&gt;&lt;/a&gt;From the sample space you can count the 10 cases where this can happen. So the probability is 10/66 = 5/33&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Using probabilities only, you work it out like this:&lt;p style="margin-bottom: 0cm;" align="left" lang="en-US"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;P(1st is type A) = 5/12&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt; &lt;p style="margin-bottom: 0cm;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;     &lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;P(2&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;sup&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;nd&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/sup&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt; is type A) = 4/11 [If the first one was an A, then there will only be 4 As left. Also, there will only be 11 samples left, as the first sample isn't replaced.]    &lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt; &lt;/p&gt; &lt;p style="margin-bottom: 0cm;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;     &lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;P(1st is type A &lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;&lt;b&gt;AND&lt;/b&gt;&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt; 2&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;sup&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;nd&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/sup&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-family:Arial,sans-serif;"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt; is type A) = 5/12 x 4/11 = 20/132 = 5/33&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;&lt;br /&gt;Looking at part (ii):&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/SCdMKG0h8tI/AAAAAAAAAFM/rEWLv2s7a_k/s1600-h/1999probpart2.jpg"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/SCdMKG0h8tI/AAAAAAAAAFM/rEWLv2s7a_k/s400/1999probpart2.jpg" alt="" id="BLOGGER_PHOTO_ID_5199208031335871186" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Counting from the sample space you get 12/66 = 2/11.&lt;br /&gt;Working this out using probabilities is trickier.&lt;br /&gt;Here you have to remember that there are two ways this could happen. The first way is that you get a B first, then an O, &lt;span style="font-weight: bold;"&gt;OR &lt;/span&gt;the second is the other way around. In both cases you have to remember that you are choosing from 12 the first time you pick and from 11 the second time.&lt;br /&gt;The probabilities work out like this:&lt;br /&gt;P(B then O  &lt;span style="font-weight: bold;"&gt;OR  &lt;/span&gt;O then B) :&lt;br /&gt;Work out P(B then O) first:&lt;br /&gt;P(1st is type B) = 4/12&lt;br /&gt;P(2nd is type O) = 3/11&lt;br /&gt;So P(B AND O) = 4/12 x 3/11 = 12/132&lt;br /&gt;Then work out P(O then B)&lt;br /&gt;P(1st is type O) = 3/12&lt;br /&gt;P(2nd is type B) = 4/11&lt;br /&gt;So P(O AND B) = 3/12 x 4/11 = 12/132&lt;br /&gt;(Note you could have assumed that you "B followed by O" is equally likely as "O followed by B" so that probabilities would be the same).&lt;br /&gt;Now work out P(B then O  &lt;span style="font-weight: bold;"&gt;OR  &lt;/span&gt;O then B)&lt;br /&gt;= P(B then O) + P(O then B)&lt;br /&gt;= 12/132 + 12/132&lt;br /&gt;= 24/132&lt;br /&gt;= 12/66 (same as sample space above)&lt;br /&gt;Simplify to 2/11.&lt;br /&gt;&lt;br /&gt;Looking at part (iii):&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_Edu5_KEGUdY/SCdPs20h8uI/AAAAAAAAAFU/YFRGVUnx024/s1600-h/1999probpart3.jpg"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://2.bp.blogspot.com/_Edu5_KEGUdY/SCdPs20h8uI/AAAAAAAAAFU/YFRGVUnx024/s400/1999probpart3.jpg" alt="" id="BLOGGER_PHOTO_ID_5199211926871208674" border="0" /&gt;&lt;/a&gt;From the sample space you can see that this can occur 19 ways out of 66 so P(both the same type) = 19/66.&lt;br /&gt;Using probabilities, you need to consider what is a successful outcome. If you write out what "of the same blood type" means, you will see that a successful outcome is "both A &lt;span style="font-weight: bold;"&gt;OR &lt;/span&gt;both B &lt;span style="font-weight: bold;"&gt;OR &lt;/span&gt;both O", so you need to add P(both A) + P(both B) + P(both O).&lt;br /&gt;You have already found the probabilty of both samples being type A in part (i).&lt;br /&gt;The answer was 10/66 or 5/33.&lt;br /&gt;Now you need to find the probability of both being B and the probability of both being O.&lt;br /&gt;P(Both B) = 4/12 x 3/11 = 12/132 = 6/66&lt;br /&gt;P(Both O) = 3/12 x 2/11 = 6/132 = 3/66&lt;br /&gt;(I am keeping all fractions with 66 as common denominator on purpose).&lt;br /&gt;Now add&lt;br /&gt;P(Both A &lt;span style="font-weight: bold;"&gt;OR &lt;/span&gt;both B &lt;span style="font-weight: bold;"&gt;OR &lt;/span&gt;both O) = 10/66 + 6/66 + 3/33 = 19/66&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-64142265493489969?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/64142265493489969/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=64142265493489969' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/64142265493489969'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/64142265493489969'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/probability-question.html' title='Probability Question'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/SCdKcG0h8rI/AAAAAAAAAE8/hf8s80stYR8/s72-c/1999prob.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7646146062041289962</id><published>2008-05-11T12:07:00.000-07:00</published><updated>2008-05-11T12:18:20.965-07:00</updated><title type='text'>Mini-mock Paper 2 Feedback</title><content type='html'>&lt;span style="font-family: arial;"&gt;For the Trigonometry question, you just had to know your Trig ratios sin=opp/hyp etc and apply them to the triangle. It wasn't necessary to work out the exact answer. You lost marks if you didn't give the answer as a fraction.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;The question on Co-ordinate Geometry of the circle was well answered. You had to use the midpoint formula to find the centre of the circle.&lt;/span&gt;&lt;br /&gt;  &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;i&gt;Centre of S is midpoint of diameter.&lt;/i&gt;&lt;span lang="en-US"&gt;&lt;i&gt;&lt;span style="text-decoration: none;"&gt; (1,-2)&lt;/span&gt;&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;     &lt;br /&gt;&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt; &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;Radius = distance f&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;om either endpoint of diameter (e.g. (-1,-1)) to the centre &lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;&lt;span style="text-decoration: none;"&gt;(1,-2)&lt;/span&gt;&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;. (or half the diameter)&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt; &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;= &lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;√&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;(1&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;+1)&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;²&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt; + (-2+1)&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;²&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt; &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;= &lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;√5&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;  &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;Now use radius √5 and centre &lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;&lt;span style="text-decoration: none;"&gt;(1,-2)&lt;/span&gt;&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt; to form equation of circle:&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt; &lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;(x – 1)&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:85%;"&gt;&lt;span lang="en-US"&gt;&lt;i&gt;² + (y + 2)² = 5&lt;/i&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;&lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;span style="font-family: arial;"&gt;The simpson's rule was straightforward and was well answered in general.&lt;/span&gt;&lt;/p&gt;&lt;p style="margin-bottom: 0cm; font-family: arial;" align="left"&gt;&lt;br /&gt;&lt;span style="font-family: arial;"&gt;&lt;/span&gt;&lt;/p&gt;Nobody got the probability question right - I am going to create a full post about that.&lt;br /&gt;&lt;br /&gt;The Linear programming question was tricky, because it was easy to overlook the "number of drivers av&lt;a href="javascript:void(0)" tabindex="10" onclick="return false;"&gt;&lt;span&gt;&lt;/span&gt;&lt;/a&gt;ailable" as a limitation. Most people who got this second inequality right got the correct solution.&lt;br /&gt;NB: Don't forget that you must use simultaneous equations to find the vertex at the intersection of the two lines.&lt;br /&gt;&lt;br /&gt;By the way, it looks like we will have only one class left before Friday, so have your questions ready.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7646146062041289962?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7646146062041289962/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7646146062041289962' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7646146062041289962'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7646146062041289962'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/mini-mock-paper-2-feedback.html' title='Mini-mock Paper 2 Feedback'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6183314464166610690</id><published>2008-05-08T13:56:00.000-07:00</published><updated>2008-11-12T21:09:24.363-08:00</updated><title type='text'>Paper 1 feedback</title><content type='html'>Following the mini-mock exam yesterday, there were a few noteworthy common errors.&lt;br /&gt;&lt;br /&gt;Firstly, lots of students lost marks by not following instructions exactly.&lt;br /&gt;&lt;ul&gt;&lt;li&gt;The solution set of an inequality isn't n&amp;lt;4. You have to list the elements as {0,1,2,3} or graph this on a number line.&lt;/li&gt;&lt;li&gt;The cooking instructions question asked for the time in hours and minutes - if you gave it in minutes only, you lost marks.&lt;/li&gt;&lt;li&gt;On the functions question, you were asked for the co-ordinates of the local max and min - if you only gave the values of x for which the max and min occur, you lose marks.&lt;/li&gt;&lt;/ul&gt;Every time you get a blunder (-3) you are effectively losing ½%&lt;br /&gt;&lt;br /&gt;In the differentiation question there are still issues.&lt;br /&gt;Right throughout the first principles question there are opportunities to lose marks. The main one that &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/differentiation-test.html"&gt;we've covered before&lt;/a&gt; is not having a left-hand-side, and not mentioning the concept of a limit.&lt;br /&gt;Also lots of students cancelled&lt;br /&gt;3h² + 6xh + h&lt;br /&gt;--------------------&lt;br /&gt;         h&lt;br /&gt;to get&lt;br /&gt;3h + 6x&lt;br /&gt;forgetting that h/h = 1&lt;br /&gt;&lt;br /&gt;The complex numbers question was poorly answered. This needs to be revised. The previous entry on complex numbers is &lt;a href="http://leavingcertmaths.blogspot.com/2008/03/complex-numbers.html"&gt;here&lt;/a&gt;.&lt;br /&gt;&lt;br /&gt;Also, the performance on the laws of indices question was weak.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SCNvMPOWHDI/AAAAAAAAAEU/qUKqZmF-F18/s1600-h/lawsindices.bmp"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SCNvMPOWHDI/AAAAAAAAAEU/qUKqZmF-F18/s320/lawsindices.bmp" alt="" id="BLOGGER_PHOTO_ID_5198120650951498802" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Almost everyone got caught on the second question where each part of the equation was already in the form 2 to the power of something. This was a part (c) question so it is unlikely to be so simple. You must work out the right-hand-side&lt;br /&gt;(64 - 32 = 32 = 2^5) and then equate the powers.&lt;br /&gt;This is also a good place to demonstrate the value of checking your answer.&lt;br /&gt;If you do the question &lt;span style="font-weight: bold;"&gt;wrong&lt;/span&gt;:&lt;br /&gt;3p-7 = 6-5&lt;br /&gt;3p = 8&lt;br /&gt;p = 8/3&lt;br /&gt;Try substituting this back in to the original and you will see that it doesn't balance.&lt;br /&gt;The &lt;span style="font-weight: bold;"&gt;correct way&lt;/span&gt; is to recognise that the RHS ends up as 2^5 and then equating the powers correctly, you get:&lt;br /&gt;3p -7 = 5&lt;br /&gt;3p = 12&lt;br /&gt;p = 4&lt;br /&gt;&lt;br /&gt;Also, don't forget ... always make an attempt. Many attempts are work 3 marks - which is ½%&lt;br /&gt;&lt;br /&gt;In tomorrow's double, we will take a general look at Paper 2 and then we'll do a Paper 2 mini-mock in our second period.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6183314464166610690?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6183314464166610690/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6183314464166610690' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6183314464166610690'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6183314464166610690'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/paper-1-feedback.html' title='Paper 1 feedback'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/SCNvMPOWHDI/AAAAAAAAAEU/qUKqZmF-F18/s72-c/lawsindices.bmp' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6529300418800506563</id><published>2008-05-06T15:33:00.000-07:00</published><updated>2008-05-06T15:36:41.159-07:00</updated><title type='text'>Last bits of revision</title><content type='html'>In tomorrow's class we will have a Paper 1 mini-mock exam.&lt;br /&gt;On Thursday we will do a proper revision of co-ordinate geometry of the circle as this topic seems to be still causing problems for many.&lt;br /&gt;On Friday we will have a Paper 2 mini-mock and then resume revision, including probability.&lt;br /&gt;&lt;br /&gt;We'll also cover general exam approach and prep over the next few days.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6529300418800506563?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6529300418800506563/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6529300418800506563' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6529300418800506563'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6529300418800506563'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/last-bits-of-revision.html' title='Last bits of revision'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-3365766374855890311</id><published>2008-05-01T07:43:00.000-07:00</published><updated>2008-05-05T12:11:35.671-07:00</updated><title type='text'>Perimeter Area and Volume</title><content type='html'>For my one-page overview you can look at the &lt;a href="http://leavingcertmaths.blogspot.com/2008/02/perimeter-area-volume.html"&gt;previous entry&lt;/a&gt;.&lt;br /&gt;&lt;br /&gt;In class on Thursday, we looked at the different types of questions you can get asked for perimeter, area and volume.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Finding  area and perimeter of  rectangular shapes and triangles&lt;/span&gt;&lt;br /&gt;Irregular rectangular shapes: break them into smaller rectangles.&lt;br /&gt;Triangles: half the base by the perpendicular height.&lt;br /&gt;[Area of a triangle of where base = 8cm and perpendicular height = 3cm multiply as follows&lt;br /&gt;1/2 x 8 x 3 = 12cm²]&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Volume of a prism&lt;/span&gt; (any rectangular solid with a uniform cross-section)&lt;br /&gt;Find the area of the uniform cross-section and multiply this by the length of the prism.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Circular shapes&lt;/span&gt;&lt;br /&gt;The first question is how to handle π, pi.&lt;br /&gt;The most important thing is to follow instructions, using 22/7, 3.14 or giving your answer in terms of π.&lt;br /&gt;Know where to find the formulae you need.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;Trickier questions&lt;/span&gt;&lt;br /&gt;&lt;span style="font-style: italic;"&gt;Changing shapes&lt;/span&gt;&lt;br /&gt;If a solid in one shape is being melted down and recast into another shape you need to set up an equation. If both shapes are circular (eg a sphere being melted down into a cylinder, or liquid in a cylindrical jug being poured into smaller cylindrical tumblers) then the πs on both sides of the equation will cancel. In questions like this you will not be told how to handle π.&lt;br /&gt;&lt;span style="font-style: italic;"&gt;Liquid in a pipe&lt;/span&gt;&lt;br /&gt;Water flows in a pipe at the rate if 50cm/sec. The pipe has a radius of 2cm. How long will it take to fill a tank measuring 30cm x 30cm x 100cm.&lt;br /&gt;To answer a question like this, consider a single molecule of H2O in the pipe. It takes 1 second to travel 50cm - that means that in the space of 1 second all the molecules are replaced. If you find the volume of 50cm of pipe you will have 1 second's worth of water.&lt;br /&gt;[This is π x 4² x 50]&lt;br /&gt;Then find the volume of the tank&lt;br /&gt;[This is 30 x 30 x 50]&lt;br /&gt;Finally divide the first answer into the second answer to find the time in seconds.&lt;br /&gt;Then convert to minutes or hours as required.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-3365766374855890311?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/3365766374855890311/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=3365766374855890311' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3365766374855890311'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/3365766374855890311'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/05/look-at-previous-entry.html' title='Perimeter Area and Volume'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-1612812704362529670</id><published>2008-04-30T11:48:00.000-07:00</published><updated>2008-11-12T21:09:25.130-08:00</updated><title type='text'>Simpson's Rule</title><content type='html'>Today we looked at the application of Simpson's rule for working out the area of an irregular shape.&lt;br /&gt;&lt;br /&gt;The shape is divided into an even number of strips which are of equal width.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_Edu5_KEGUdY/SBjFh1jAoxI/AAAAAAAAADs/cTSz4zQzaIk/s1600-h/simpsons2.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://2.bp.blogspot.com/_Edu5_KEGUdY/SBjFh1jAoxI/AAAAAAAAADs/cTSz4zQzaIk/s320/simpsons2.jpg" alt="" id="BLOGGER_PHOTO_ID_5195119355272143634" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;You are given a shape like this (taken from LC paper 2005).&lt;br /&gt;It is divided into an even number of strips (in this case 6) and each strip is bounded by a strip length. As there are 6 strips there are 7 strip lengths.&lt;br /&gt;&lt;br /&gt;Note that the last strip length is zero.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBjGxVjAoyI/AAAAAAAAAD0/MTlTCqYA588/s1600-h/simpsons2.jpg"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBjGxVjAoyI/AAAAAAAAAD0/MTlTCqYA588/s320/simpsons2.jpg" alt="" id="BLOGGER_PHOTO_ID_5195120721071743778" border="0" /&gt;&lt;/a&gt;First step is to label each strip length as odd or even.&lt;br /&gt;&lt;br /&gt;&lt;- Like this.       &lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Now apply Simpson's rule.         &lt;br /&gt;The rule is that the area of this shape&lt;br /&gt;= w/3(First + last + 2(sum of odds) + 4(sum of evens)) &lt;br /&gt;Filling this in:&lt;br /&gt;area = 18/3 (10 + 0 + 2(30 + 36) + 4 (25 + 38 + 22))&lt;br /&gt;= 6(10 + 132 + 340)&lt;br /&gt;= 6(482)&lt;br /&gt;= 2892m²&lt;br /&gt;&lt;br /&gt;[As it is easy to make an error in the adding and multiplying, it is a good habit to do a rough check - to make sure that your answer is in the right ballpark. You can check this by approximating the average length of strip and multiplying by the total width. Width = 18 x 6 =  108 Average length = 26 (rough estimate) Ballpark for area = 108 x 26 = 2808m%sup2;]&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/SBi_0FjAovI/AAAAAAAAADc/K07DAUmTYpg/s1600-h/simpsons1.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/SBi_0FjAovI/AAAAAAAAADc/K07DAUmTYpg/s320/simpsons1.jpg" alt="" id="BLOGGER_PHOTO_ID_5195113071734989554" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;In this diagram, there are 4 (an even number) strips, and there are two sets of measurements for each strip.&lt;br /&gt;&lt;br /&gt;Label the strip lengths as odd or even and add the upper length to the lower one.&lt;br /&gt;&lt;br /&gt;... giving you this&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_Edu5_KEGUdY/SBjKU1jAozI/AAAAAAAAAD8/qrW0RiV1_M8/s1600-h/simpsons3.jpg"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://2.bp.blogspot.com/_Edu5_KEGUdY/SBjKU1jAozI/AAAAAAAAAD8/qrW0RiV1_M8/s320/simpsons3.jpg" alt="" id="BLOGGER_PHOTO_ID_5195124629491983154" border="0" /&gt;&lt;/a&gt;The total lengths are in green. You then sub these into the Simpson's Rule formula:&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Area = 5/3(0 + 0 + 2(11) + 4(8 + 6))&lt;br /&gt;= 5/3(22+ 56)&lt;br /&gt;= 5/3(78)&lt;br /&gt;= 130&lt;br /&gt;&lt;br /&gt;Again ballpark estimate would be: 20x 7 = 140.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Simpson's rule with Missing Values.&lt;br /&gt;There are two possibilities - either the width of each strip is missing or one of the strip lengths is missing. In either case, you will be given the area and you use it to build an equation around your unknown.&lt;br /&gt;&lt;br /&gt;In this example the strip width is not given.&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBjUtljAo0I/AAAAAAAAAEE/dP70NFyXQqQ/s1600-h/simpsons4.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBjUtljAo0I/AAAAAAAAAEE/dP70NFyXQqQ/s320/simpsons4.jpg" alt="" id="BLOGGER_PHOTO_ID_5195136049810023234" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Let's say that you are told that the&lt;br /&gt;area =  1432m²&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;You set up an equation like this:&lt;br /&gt;1432 = x/3(0 + 0 + 2(37) + 4(30+41))&lt;br /&gt;1432 = x/3(358)&lt;br /&gt;4296 = 358x&lt;br /&gt;x = 12&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;The missing value could be in the strip length.&lt;br /&gt;In fact there could be two missing values, both expressed in terms of x. For example.&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBjXeljAo1I/AAAAAAAAAEM/znhUpB7dnPs/s1600-h/simpsons5.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBjXeljAo1I/AAAAAAAAAEM/znhUpB7dnPs/s320/simpsons5.jpg" alt="" id="BLOGGER_PHOTO_ID_5195139090646868818" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;In this example, the area =  270m²&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Set up an equation:&lt;br /&gt;&lt;br /&gt;270 = 3/3(12 + x + 2(2x+18) + 4(18+22+8))&lt;br /&gt;270 = 1(12 + x + 4x + 36 + 192)&lt;br /&gt;270 = 5x + 240&lt;br /&gt;300 = 5x&lt;br /&gt;x = 6&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Note that there are a few variants of Simpson's rule.&lt;br /&gt;You could be asked to work out the area between the graph of a function and the x-axis (see 2002 question).&lt;br /&gt;You could be asked to copy a diagram, measure it and work out the area.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-1612812704362529670?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/1612812704362529670/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=1612812704362529670' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1612812704362529670'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1612812704362529670'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/simpsons-rule.html' title='Simpson&apos;s Rule'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_Edu5_KEGUdY/SBjFh1jAoxI/AAAAAAAAADs/cTSz4zQzaIk/s72-c/simpsons2.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6261550190551673225</id><published>2008-04-29T12:40:00.000-07:00</published><updated>2008-04-29T14:37:51.224-07:00</updated><title type='text'>Linear Programming - part (b)</title><content type='html'>We looked at a few linear programming problems today.&lt;br /&gt;There are 3 parts to tackling these questions.&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;STEP 1&lt;/span&gt;&lt;br /&gt;Read through the text and extract 2 inequalities.&lt;br /&gt;If you look back over the years, you will see that this question mostly comes up in a formulaic manner. In 2005 you were asked&lt;br /&gt;"A manufacturer of garden furniture produces plastic chairs and tables. Each chair requires 2 kg of raw material and each table requires 5 kg of raw material. In any working period the raw material used cannot exceed 800 kg.&lt;br /&gt;Each chair requires 4 minutes of machine time and each table requires 4 minutes of machine time. The total machine time available in any working period is 1000 minutes."&lt;br /&gt;Identify the resctrictions: the manufacturer is restricted by amount of raw material they can use and by the minutes of machine time they have available.&lt;br /&gt;x is going to be the number of chairs they manufacture, so as each chair reguires 2kg of raw material, they will require 2x kg for all the chairs they make (so if it turned out that they made 30 chairs, then they would need 2(30) = 60kg.)&lt;br /&gt;Note that the words "cannot exceed" translate to "≤" in maths.&lt;br /&gt;You build your two inequalities like this:&lt;br /&gt;Raw materials: 2x + 5y ≤ 800   &lt;br /&gt;Time: 4x + 4y ≤ 1000&lt;br /&gt;&lt;br /&gt;However in 2007, it was worded this way&lt;br /&gt;"A developer is planning a holiday complex of cottages and apartments.&lt;br /&gt;Each cottage will accommodate 3 adults and 5 children and each apartment will accommodate 2 adults and 2 children.&lt;br /&gt;The other facilities in the complex are designed for a maximum of 60 adults and a maximum of 80 children."&lt;br /&gt;Here the inequalities are not so obvious. A trick for working these out is to look at the two limiting factors - you are told that the max number of adults is 60 and the max number of children is 80.&lt;br /&gt;So you know that your inequalities will be of the form&lt;br /&gt;Adults:  ...x + ....y ≤ 60  &lt;br /&gt;and&lt;br /&gt;Children: ...x + ...y ≤ 80&lt;br /&gt; (in other words the first inequality concerns restrictions of number of adults and the second inequality concerns restrictions of number of children)&lt;br /&gt;Once you know that all the children info goes into the first inequality, you can find it more easily.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;STEP 2&lt;/span&gt;&lt;br /&gt;Graph the inequalities.&lt;br /&gt;To do this you need to write the inequalities as equations. Then plot them the way you would in coordinate geometry - the easiest way is to use the intercept method (if you've forgotten this, it is described below in the section on Question 11 part(a).&lt;br /&gt;Use the test-point to work out which half-plane you are interested in for each line. The resulting shaded in area is almost always a quadrilateral bounded by the x and y axes.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;STEP 3&lt;/span&gt;&lt;br /&gt;Evaluate an expression. After you've been asked to graph all the information you'll be told another piece of information about x and y, this time with no restriction.&lt;br /&gt;In 2005 this was "The manufacturer sells each chair for €20 and each table for €40."&lt;br /&gt;In 2007 it was "If the rental income per night will be €65 for a cottage and €40 for an apartment ...". In each case you are asked to maximise profit or revenue. You use this new information to create an expression in x and y.&lt;br /&gt;In 2005 it would be 20x + 40y&lt;br /&gt;In 2007 it would be 65x + 40y&lt;br /&gt;The optimum values occur at the vertices (corners) of the shaded region. The vertex formed by the intersection of the two lines you just graphed must be calculated using simultaneous equations. The others can be read from the graph.&lt;br /&gt;Then you take the (x,y) co-ordinates of each vertex and sub the x and y values into the expression.&lt;br /&gt;Highlight the optimal value and very important, write the answer as an english sentence.&lt;br /&gt;"The developer should build 10 cottages and 15 apartments".&lt;br /&gt;&lt;br /&gt;There is usually a final part to this question - always something different, requiring you to evaluate another expression, find a percentage, deduct some amount from the overall profit etc.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6261550190551673225?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6261550190551673225/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6261550190551673225' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6261550190551673225'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6261550190551673225'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/linear-programming-part-b.html' title='Linear Programming - part (b)'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4969066599857426847</id><published>2008-04-28T13:32:00.002-07:00</published><updated>2008-04-28T13:43:41.941-07:00</updated><title type='text'>Planning for the last few classes</title><content type='html'>I've made some updates to yesterday's post on half-planes. It is pretty comprehensive now.&lt;br /&gt;&lt;br /&gt;We should be able to cover the main part of the linear programming question should in Tuesday's class.&lt;br /&gt;&lt;br /&gt;If you take a look at the &lt;a href="http://leavingcertmaths.blogspot.com/2008/03/schedule-of-revision.html"&gt;schedule of revision&lt;/a&gt; that we agreed back in March you'll see that the only topic left to cover is perimeter area and volume - paper 2 question 1.&lt;br /&gt;I would like to get this started on Wednesday.&lt;br /&gt;&lt;br /&gt;Homework for Tuesday is the 2005 linear programming question. If you have trouble with the part (a), take a look at the end of the &lt;a href="http://leavingcertmaths.blogspot.com/2008/04/half-plane-is-region-on-co-ordinated.html"&gt;previous entry in this blog&lt;/a&gt;.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4969066599857426847?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4969066599857426847/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4969066599857426847' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4969066599857426847'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4969066599857426847'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/planning-for-last-few-classes_28.html' title='Planning for the last few classes'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2845361278881349435</id><published>2008-04-27T03:34:00.001-07:00</published><updated>2008-11-12T21:09:25.740-08:00</updated><title type='text'>Half-planes in linear programming</title><content type='html'>A half-plane is a region on a co-ordinated plane for which an inequality in x, y or both is true.&lt;br /&gt;&lt;br /&gt;The idea of graphing a half-plane (such as 2x + 3y ≤ 6) is similar to graphing a line.&lt;br /&gt;First change the inequality to an equation - graph 2x+3y = 6.&lt;br /&gt;Remember how to do this?&lt;br /&gt;Find two points on the line&lt;br /&gt;&lt;ul&gt;&lt;li&gt;set x=0, see what y is - giving you (0,2)&lt;/li&gt;&lt;li&gt;set y=0, see what x is - giving you (3,0).&lt;/li&gt;&lt;/ul&gt;Now you can graph the line.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBTdYVjAoqI/AAAAAAAAAC0/_rST7oq6wlY/s320/2xplus3yequals6.jpg" alt="" id="BLOGGER_PHOTO_ID_5194019680435610274" border="0" /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;But how do you find the half-plane 2x + 3y ≤ 6&lt;br /&gt;In other words, on which side of this line will every single point obey the rule 2x + 3y ≤ 6 ?&lt;br /&gt;To find out, you use a test point.&lt;br /&gt;The easiest test point to use is (0,0) - remember you can't use this if the line goes through the origin and you will know if goes through the origin if there is no constant (e.g. the line 2x + 3y = 0 goes through the origin).&lt;br /&gt;Substitute the test point (0,0) into 2x + 3y ≤ 6 and we get&lt;br /&gt;2(0) + 3(0) ≤ 6&lt;br /&gt;0≤6&lt;br /&gt;This last line is true, (0 is less than 6) so if 2x + 3y ≤ 6 is true for (0,0), it is also true for all other points on the same side of the line as (0,0).&lt;br /&gt;So, draw arrows pointing towards the (0,0) side like this.&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBTh6ljAosI/AAAAAAAAADE/g0yu6a5btOk/s1600-h/2xplus3ylessthan6.jpg"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/SBTh6ljAosI/AAAAAAAAADE/g0yu6a5btOk/s320/2xplus3ylessthan6.jpg" alt="" id="BLOGGER_PHOTO_ID_5194024666892640962" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;If your test point had produced result that wasn't true such as 8 ≤ 6, then the arrows would point towards the side of the line that did &lt;span style="font-weight: bold;"&gt;not &lt;/span&gt;contain the test point.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;A typical exam part (a) type question would be:&lt;br /&gt;Shade in the region of a plane which simultaneously satisfies the following inequalities:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;2x + 3y ≤ 6&lt;/li&gt;&lt;li&gt;x ≥ 1&lt;/li&gt;&lt;li&gt;y ≥ 0&lt;/li&gt;&lt;/ul&gt;The first one is already done.&lt;br /&gt;The second one works like this:&lt;br /&gt;Turn it into an equation x = 1 and graph this. Any point where x = 1 is on the line ((1,0), (1,1),  (1,2) etc) so this line is the line that cuts the x-axis at 1 and is parallel to the y-axis.&lt;br /&gt;Work out which way the arrow goes ... take a test point like (0,0) and see does it fit the inequality x ≥ 1.&lt;br /&gt;Substituting into the inequality gives 0 ≥ 1 which is not true, so the half-plane we are looking for is on the other side, arrows pointing to the right.&lt;br /&gt;&lt;br /&gt;Use the same logic to work out that y=0 is the equation for the x-axis. You can't use (0,0) as a test-point as it is on the line, so use another convenient point instead  - e.g. (0,1).&lt;br /&gt;Substituting into the inequality gives 1 ≥ 0 which is true, so this means that the test point is in the half-plane and that the arrows point upwards.&lt;br /&gt;Last part of the question is to draw shade in the region which is in all 3 half-planes.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBYkP1jAotI/AAAAAAAAADM/1bZlpqqI2L0/s1600-h/2xplus3ylessthan6xge1yge0.jpg"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBYkP1jAotI/AAAAAAAAADM/1bZlpqqI2L0/s320/2xplus3ylessthan6xge1yge0.jpg" alt="" id="BLOGGER_PHOTO_ID_5194379074709005010" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Note that there are other ways this question could be asked. You could be given the diagram and be asked for the 3 inequalities that define a region.&lt;br /&gt;&lt;br /&gt;This was the example we started looking at in class on Monday.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/SBYszljAouI/AAAAAAAAADU/zLzEfiVkvo4/s1600-h/3xplus4yequals12.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/SBYszljAouI/AAAAAAAAADU/zLzEfiVkvo4/s320/3xplus4yequals12.jpg" alt="" id="BLOGGER_PHOTO_ID_5194388484982350562" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;The vertical and horizontal lines should be easy now.&lt;br /&gt;"Above the x-azis" means the inequality is y ≥ 0&lt;br /&gt;"To the right of the y-axis" means the inequality is x ≥ 0&lt;br /&gt;&lt;br /&gt;The diagonal line is more difficult.&lt;br /&gt;You know that two points on the line are (4,0) and (0,3) so how can you get the equation of the line?&lt;br /&gt;&lt;br /&gt;You have to resurrect your co-ordinate geometry.&lt;br /&gt;First find the slope of the line&lt;br /&gt;m = 3-0/0-4 = -3/4&lt;br /&gt;&lt;br /&gt;Now put one of your points into the formula y-y1 = m(x-x1)&lt;br /&gt;I'll choose (4,0)&lt;br /&gt;This gives you:&lt;br /&gt;y - 0 = -3/4(x - 4)&lt;br /&gt;4y = -3x + 12&lt;br /&gt;Rearranging this gives us the equation&lt;br /&gt;3x + 4y = 12           ( which is the rule for being a point on the diagonal line).&lt;br /&gt;But you want rule for being on the half-plane which is below and to the left of this line.&lt;br /&gt;So you have to use a test-point.  (0,0) is a good candidate here.&lt;br /&gt;&lt;br /&gt;3x + 4y = 12&lt;br /&gt;Left-hand-side works out as 3(0) + 4(0) which is 0.&lt;br /&gt;Right hand side is 12.&lt;br /&gt;&lt;br /&gt;Now you have to work out the direction of the inequality:&lt;br /&gt;0 ? 12&lt;br /&gt;Answer is that 0 &amp;lt; 12 so in this case the inequality that defines the half-plane in question is&lt;br /&gt;3x + 4y ≤ 12&lt;br /&gt;&lt;br /&gt;A few closing points:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;If you are doing this question in your exam, make sure that you write out all three inequalities clearly.&lt;/li&gt;&lt;li&gt;On our course the half-planes are always defined using ≤ or ≥, not &amp;lt; or &amp;gt;.&lt;/li&gt;&lt;li&gt;Also, note that part (b) of this question will be concerned with positive x and y values (since they refer to real-world problems) , but in part (a) you could have lines that intercept the x and/or y-axes at negative numbers.&lt;/li&gt;&lt;/ul&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2845361278881349435?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2845361278881349435/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2845361278881349435' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2845361278881349435'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2845361278881349435'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/half-plane-is-region-on-co-ordinated.html' title='Half-planes in linear programming'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/SBTdYVjAoqI/AAAAAAAAAC0/_rST7oq6wlY/s72-c/2xplus3yequals6.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-5338561166291269339</id><published>2008-04-24T15:40:00.000-07:00</published><updated>2008-11-12T21:09:25.941-08:00</updated><title type='text'>Linear Programming</title><content type='html'>For most of the class, the linear programming question will be the only question we prepare for in section B of paper 2. You re-use your co-ordinate geometry and algebra skills (particularly linear inequalities and simultaneous equations) which you need anyway for other parts of the exam. The linear programming problem is quite formulaic - if you practice a few you will see the pattern and be able to get a good mark on this part of the exam. Don't forget to write the answer as an english sentence at the end of your answer.&lt;br /&gt;&lt;br /&gt;The linear programming question is almost always in two parts.&lt;br /&gt;a) worth 15 marks asks about half-planes&lt;br /&gt;b) is the linear programming problem.&lt;br /&gt;&lt;br /&gt;Homework this evening involves solving the question from 2000 (paper 2 Question 11).&lt;br /&gt;&lt;br /&gt;Here is a 1-page overview of this question.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBEOYFjAonI/AAAAAAAAACU/Rj4uVVuJe24/s1600-h/p2q11.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SBEOYFjAonI/AAAAAAAAACU/Rj4uVVuJe24/s320/p2q11.gif" alt="" id="BLOGGER_PHOTO_ID_5192947652303561330" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-5338561166291269339?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/5338561166291269339/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=5338561166291269339' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5338561166291269339'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5338561166291269339'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/linear-programming.html' title='Linear Programming'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/SBEOYFjAonI/AAAAAAAAACU/Rj4uVVuJe24/s72-c/p2q11.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7052162305993988433</id><published>2008-04-23T12:37:00.000-07:00</published><updated>2008-04-23T12:57:52.959-07:00</updated><title type='text'>Finishing statistics</title><content type='html'>Today we looked at the 2006 question in statistics.&lt;br /&gt;The main points points that we went over were:&lt;br /&gt;calculating standard deviation&lt;br /&gt;finding the mean using mid-interval values&lt;br /&gt;producing histograms&lt;br /&gt;For calculating the standard deviation you should format your work into columns, working out the differences from the mean, then the differences squared (then this value x the frequencies if applicable) etc. If doesn't matter if your work isn't in columns, as long as you follow the correct steps and show your work. As a rule of thumb, almost all your data should be within 2 std deviations above and below the mean. This means that the value of the std deviation should not be more than 1/2 the mean.&lt;br /&gt;Whenever you are finding the mean value from a set of data you should check your answer to see if it is &lt;span style="font-style: italic;"&gt;reasonable&lt;/span&gt;. The most common error when finding the mean of a frequency distribution is to divide by the number of categories instead of the sum of the frequencies. If you do this, your mean will be much too large and it should be obvious that you've made a mistake.&lt;br /&gt;The purpose of histograms is to distribute data across uneven intervals.  It is not a straightforward bar chart. You should write the frequency in a circle in each block. You can use the alternative format of histogram which has a key showing e.g. one square = 5 cars (in the 2006 question).&lt;br /&gt;&lt;br /&gt;Homework for tonight is the 2005 statistics question. This one includes weighted mean and std deviation of a frequency distribution. If you can do the statistics questions from 2005 to 2007 you will have covered the topic pretty comprehensively.&lt;br /&gt;&lt;br /&gt;On Friday in the double class 2nd period we will have a test (statistics + maybe lin programming also).&lt;br /&gt;Tomorrow, once we have corrected the homework, we will go on to Linear Programming.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7052162305993988433?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7052162305993988433/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7052162305993988433' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7052162305993988433'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7052162305993988433'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/finishing-statistics.html' title='Finishing statistics'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-238877120425453295</id><published>2008-04-21T14:42:00.001-07:00</published><updated>2008-11-12T21:09:26.081-08:00</updated><title type='text'>Statistics</title><content type='html'>We will revise statistics for the next few classes.&lt;br /&gt;The main skills you need for this question are:&lt;br /&gt;- being able to work with frequency distributions in their various forms&lt;br /&gt;- being able to calculate standard deviations&lt;br /&gt;- being able to graph data using histograms and ogives&lt;br /&gt;- being able to interpret graphs ( remember to show the markings that indicate how you work out e.g. median or mean from your graphs)&lt;br /&gt;&lt;br /&gt;We will go over the topics that came up in the 2007 paper in class tomorrow.&lt;br /&gt;&lt;br /&gt;Here is the 1-page overview for statistics.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/SA0LKyTKZCI/AAAAAAAAACM/mu9x4j_WcFw/s1600-h/p2q7.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/SA0LKyTKZCI/AAAAAAAAACM/mu9x4j_WcFw/s320/p2q7.gif" alt="" id="BLOGGER_PHOTO_ID_5191818225356792866" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-238877120425453295?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/238877120425453295/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=238877120425453295' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/238877120425453295'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/238877120425453295'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/statistics.html' title='Statistics'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_Edu5_KEGUdY/SA0LKyTKZCI/AAAAAAAAACM/mu9x4j_WcFw/s72-c/p2q7.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2593057926467197174</id><published>2008-04-21T14:40:00.000-07:00</published><updated>2008-11-12T21:09:26.853-08:00</updated><title type='text'>Finishing up Differentiation</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_Edu5_KEGUdY/SA0KKCTKZBI/AAAAAAAAACE/9Gzh4Kte9cw/s1600-h/p1q8.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://2.bp.blogspot.com/_Edu5_KEGUdY/SA0KKCTKZBI/AAAAAAAAACE/9Gzh4Kte9cw/s320/p1q8.gif" alt="" id="BLOGGER_PHOTO_ID_5191817112960263186" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;To round off this topic, here is the 1-page overview.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2593057926467197174?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2593057926467197174/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2593057926467197174' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2593057926467197174'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2593057926467197174'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/finishing-up-differentiation.html' title='Finishing up Differentiation'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_Edu5_KEGUdY/SA0KKCTKZBI/AAAAAAAAACE/9Gzh4Kte9cw/s72-c/p1q8.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6839314632694433906</id><published>2008-04-18T09:28:00.000-07:00</published><updated>2008-11-12T21:09:27.034-08:00</updated><title type='text'>Differentiation test</title><content type='html'>Everyone did well on the main question in today's test - a really strong performance on this question.&lt;br /&gt;&lt;br /&gt;The differentiating from first principles was a little dodgy though.&lt;br /&gt;I have annotated a typical marking scheme for this, so you can see where you would pick up blunders B(-3), slips S(-1) or misreadings M(-1). Nobody made the dreaded "worthless" W(0) grade.&lt;br /&gt;&lt;br /&gt;The main issue is that many students leave out the left hand side (abbreviated as LHS). The process of differentiation only makes sense if you include the left hand side. In today's test, several students wrote things like 4x - x^2 = 4 - 2x which doesn't make any sense. &lt;br /&gt;&lt;br /&gt;Read through the this marking scheme (taken from the 2005 exam). We will go through it on Monday and I will get everyone to mark their own first principles answer according to this outline.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/SAjNJgPmRqI/AAAAAAAAAB8/p2YktDcg3Zk/s1600-h/firstprinciplesmarkingscheme.jpg"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/SAjNJgPmRqI/AAAAAAAAAB8/p2YktDcg3Zk/s320/firstprinciplesmarkingscheme.jpg" border="0" alt=""id="BLOGGER_PHOTO_ID_5190624133702370978" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6839314632694433906?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6839314632694433906/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6839314632694433906' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6839314632694433906'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6839314632694433906'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/differentiation-test.html' title='Differentiation test'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/SAjNJgPmRqI/AAAAAAAAAB8/p2YktDcg3Zk/s72-c/firstprinciplesmarkingscheme.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-5888906751829553581</id><published>2008-04-16T12:27:00.000-07:00</published><updated>2008-04-16T12:52:51.647-07:00</updated><title type='text'>Differentiating from first principles</title><content type='html'>&lt;span style="font-family:arial;"&gt;This question comes up frequently (not every year) in the Leaving Cert. When it comes up, you usually have to differentiate a quadratic, though you should practice differentiating linear functions (e.g. f(x) = 4x -1) also. It is usually worth 20 marks.&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;The way I approach it is to set up the derivative function as if you were finding the slope using the slope formula m = (y2-y1)/(x2-x1).&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;Today's example which we did in class was &lt;/span&gt;&lt;style type="text/css"&gt;  &lt;!--   @page { size: 21cm 29.7cm; margin: 2cm }   P { margin-bottom: 0.21cm }  --&gt;  &lt;/style&gt; &lt;p  style="margin-bottom: 0cm; text-decoration: none;font-family:arial;" lang="en-US"&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x²-4x+2 &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;&lt;span style="font-size:100%;"&gt;(I think)&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;x1 = x&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;y1 = &lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x²-4x+2&lt;br /&gt;x2 = x + h&lt;br /&gt;y2 = &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3(x+h)²-4(x+h)+2&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;If you plug these into the slope formula and multiply out the y2 and watch your signs with y1, you'll get&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;m =&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;²&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;+3h² +6xh -4x-4h+2 - &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x²+4x-2&lt;br /&gt;------------------------------------------------&lt;br /&gt;  x + h - x&lt;br /&gt;&lt;br /&gt;= &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3h² +6xh -4h&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;---------------&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;     h&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;= 3h +6x -4&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;Now apply the Limit as h tends towards zero (you'll lose marks if you don't do this part properly)&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;Lim   [&lt;/span&gt;&lt;span style="font-family:arial;"&gt;f(x+h) - f(x)]&lt;/span&gt;&lt;span style="font-family:arial;"&gt;/h = 6x -4&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family:arial;"&gt;h-&gt;0 &lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;        &lt;br /&gt;Also, write down somewhere either f(x) = &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x²-4x+2 and f'(x) = 6x -4&lt;br /&gt;&lt;br /&gt;or&lt;br /&gt;y = &lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;3x²-4x+2&lt;br /&gt;&lt;br /&gt;dy&lt;br /&gt;-- = 6x -4&lt;br /&gt;dx&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);font-family:arial;" &gt;&lt;span style="font-size:100%;"&gt;It is worth spending time practicing and understanding this process. You only have to do it if you are specifically asked to differentiate "from first principles", but it is central to figuring out other topics in functions and differentiation, and it gives you an application of coordinate geometry and practice at some tricky algebra.&lt;br /&gt;&lt;br /&gt;I have a worksheet that I didn't have time to distribute today that gives a worked example and practice of differentiating from first principles.&lt;br /&gt;&lt;br /&gt;We'll look at the rules for differentiating (product, quotient and chain rules) tomorrow.&lt;br /&gt;Test on Friday.&lt;br /&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-5888906751829553581?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/5888906751829553581/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=5888906751829553581' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5888906751829553581'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5888906751829553581'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/differentiating-from-first-principles.html' title='Differentiating from first principles'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-5373538278398207599</id><published>2008-04-15T14:23:00.000-07:00</published><updated>2008-04-15T14:27:08.633-07:00</updated><title type='text'>Finishing Functions, Graphs and Differentiation.</title><content type='html'>We need to finish functions, graphs and our calculus.&lt;br /&gt;In tomorrow's class we will look at differentiating from first principles and at how to apply the different rules (product, quotient and chain rules).&lt;br /&gt;Everyone should do the 2007 Q6,7,8 and 1999 Q7,8 &lt;span style="font-weight: bold;"&gt;at least&lt;/span&gt;.&lt;br /&gt;&lt;br /&gt;We'll have a class test on Thursday.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-5373538278398207599?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/5373538278398207599/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=5373538278398207599' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5373538278398207599'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5373538278398207599'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/finishing-functions-graphs-and.html' title='Finishing Functions, Graphs and Differentiation.'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4557862586606611258</id><published>2008-04-14T15:15:00.000-07:00</published><updated>2008-11-12T21:09:27.221-08:00</updated><title type='text'>Functions and Graphs</title><content type='html'>We are working on functions and graphs at the moment.&lt;br /&gt;&lt;br /&gt;In today's class we looked at how you can use a function to solve a related function.&lt;br /&gt;Using graphs of functions to find the roots of a polynomial is a key skill.&lt;br /&gt;When you graph a function, you find the output values for a selection of discreet input values.&lt;br /&gt;When you join the dots with a smooth curve you are extrapolating the output values of the input values in between. That is why we graph functions.&lt;br /&gt;Wherever your line crosses the x-axis, the output value is 0 - don't forget equation of the x-axis is y=0.  So you can use these points to work out the roots of a cubic equation.&lt;br /&gt;We looked at the 1999 q8 question on functions. This included working out a related function. Make sure you do this question and are able to follow it.&lt;br /&gt;When you split the related cubic function into the original cubic and a related linear function, you can work out the roots of the related function by reading the points of intersection from your graph.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/SAPa5APmRpI/AAAAAAAAAB0/jTX2nvjKoik/s1600-h/p1q6.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/SAPa5APmRpI/AAAAAAAAAB0/jTX2nvjKoik/s320/p1q6.gif" alt="" id="BLOGGER_PHOTO_ID_5189231868513765010" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Other points on functions which you need to know are mentioned in the 1 page overview.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4557862586606611258?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4557862586606611258/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4557862586606611258' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4557862586606611258'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4557862586606611258'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/functions-and-graphs.html' title='Functions and Graphs'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/SAPa5APmRpI/AAAAAAAAAB0/jTX2nvjKoik/s72-c/p1q6.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-1569094528674180749</id><published>2008-04-08T12:28:00.000-07:00</published><updated>2008-11-12T21:09:27.457-08:00</updated><title type='text'>Algebra</title><content type='html'>We are spending a few days revising algebra. This is a really important topic as it comes up all over the paper 1 and 2 as well as in 2 algebra-only questions (Paper 1 Q2 and Q3).&lt;br /&gt;&lt;br /&gt;We started by looking at the 2007 questions.&lt;br /&gt;Q2 involved solving inequalities. Key points:&lt;br /&gt;- know how to graph on the numberline or work out the solution set = { , , } if x is an element of N, Z and R&lt;br /&gt;- know how to handle cases like -x &lt;&gt;3 ]&lt;br /&gt;&lt;br /&gt;It also involved manipulating indices. It is too difficult to format the rules here... look them up in your book and make sure you know them. With equations, get the same number raised to different powers on each side of the =.&lt;br /&gt;Eg 2^(x+1) = 4^x&lt;br /&gt;rewrite 4^x as (2^2)^x or 2^2x&lt;br /&gt;Then equate the powers:&lt;br /&gt;x+1 = 2x&lt;br /&gt;x = 1&lt;br /&gt;&lt;br /&gt;We will look at the rest of Q2 and Q3 tomorrow. Here is a  slightly revised version of the algebra 1-page overview.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/R_vM_lUViTI/AAAAAAAAABk/YXdH7vsMkO8/s1600-h/p1q2and3.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/R_vM_lUViTI/AAAAAAAAABk/YXdH7vsMkO8/s320/p1q2and3.gif" alt="" id="BLOGGER_PHOTO_ID_5186964788568492338" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-1569094528674180749?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/1569094528674180749/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=1569094528674180749' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1569094528674180749'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1569094528674180749'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/algebra.html' title='Algebra'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_Edu5_KEGUdY/R_vM_lUViTI/AAAAAAAAABk/YXdH7vsMkO8/s72-c/p1q2and3.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-537403174644456008</id><published>2008-04-07T09:34:00.000-07:00</published><updated>2008-11-12T21:09:27.668-08:00</updated><title type='text'>More trigonometry</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/R_pRclUViSI/AAAAAAAAABc/RF3Qhmblt3s/s1600-h/p2q5.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/R_pRclUViSI/AAAAAAAAABc/RF3Qhmblt3s/s320/p2q5.gif" alt="" id="BLOGGER_PHOTO_ID_5186547472366143778" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;The unit circle, compound angles etc took longer than planned on Friday. As I said in class, these topics come up infrequently, so if you are aiming to pass this question, make sure that you are able to use sin=opp/hyp etc, sine rule, cosine rule and area of triangle.&lt;br /&gt;&lt;br /&gt;I forgot to post the 1-page overview of trigonometry last time.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Also, I will mention this in tomorrow's class, but there is one thing you should be aware of when using the Sine rule:&lt;br /&gt;If you use your calculator to work out the inverse sine of 0.9897, your calculator will tell you it is 81.7 degrees ... which it is. But, it is also the sine of 97.3 degrees. You know from the discussion of unit circle that there are two possible angles that have the same sine, cosine and tan. Our calculators always return the angle that is between 0 and 90 degrees only, not the obtuse alternative.&lt;br /&gt;Look at &lt;a href="http://www.examinations.ie/archive/exampapers/2003/LC003GLP200EV.pdf"&gt;2003 P2 Q5&lt;/a&gt; for an example where this can cause problems.&lt;br /&gt;If you solve (c) (ii) by putting&lt;br /&gt;Sin60/7 = SinA/8&lt;br /&gt;you will get the wrong answer.&lt;br /&gt;The problem here is that the shorter side of the triangle (3) is not used in this equation and so the triangle where we have a known angle (60) and two other sides (7 and 8) is not a well defined triangle. In effect, it is ASS (angle, side, side) rather than SAS (side, angle, side)! (remember the 4 conditions for congruence of triangles that you learned: SSS,SAS,ASA,RHS)&lt;br /&gt;You have to use the acute angle to work it out.&lt;br /&gt;Sin60/7 = SinB/3  ... which gives you 22 degrees for that angle and leaves 98 degrees for the obtuse angle (60 + 22 + 98 = 180).&lt;br /&gt;&lt;br /&gt;How do you know which angle to go for? A triangle can have at most 1 obtuse angle (&gt; 90 degrees) and that will be opposite the longest side.&lt;br /&gt;If you have a choice, solve the acute angle, opposite the shortest side, first.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-537403174644456008?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/537403174644456008/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=537403174644456008' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/537403174644456008'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/537403174644456008'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/more-trigonometry.html' title='More trigonometry'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/R_pRclUViSI/AAAAAAAAABc/RF3Qhmblt3s/s72-c/p2q5.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-1032091275423604799</id><published>2008-04-03T10:21:00.000-07:00</published><updated>2008-04-03T10:35:24.755-07:00</updated><title type='text'>Trigonometry</title><content type='html'>There are two parts to the trigonometry course.&lt;br /&gt;&lt;br /&gt;The first part relates to finding missing sides and angles or the area of a triangle:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;application of the trigonometric ratios for sin, cos and tan (sin=opp/hyp etc.) for right-angled triangles&lt;/li&gt;&lt;li&gt;application of the sine rule for cases where you have one complete and one incomplete "angle and opposite side" pair&lt;/li&gt;&lt;li&gt;application of cosine rule where you have 2 sides and the angle between them, or just 3 sides of a triangle&lt;/li&gt;&lt;li&gt;application of area of triangle rule 1/2 ab SinC&lt;/li&gt;&lt;/ul&gt;This is relatively straightforward and covers about 90% of the questions that come up on the exam.&lt;br /&gt;&lt;br /&gt;The second part relates to compound angles, angles &gt; 90 degrees, compass directions, unit circle, handling special angles (30, 45 and 60 degrees) using surds. This is the second half of the chapter.&lt;br /&gt;&lt;br /&gt;In today's class we went through the 2007 trigonometry question which involved material from the first list above. You have to go back quite a few years to find a question that involves compound angles, angles which are &gt; 90 degrees etc.&lt;br /&gt;&lt;br /&gt;Homework for tonight was the 2006 Trig question.&lt;br /&gt;&lt;br /&gt;In tomorrow's class we will tackle the second part of the trigonometry course.&lt;br /&gt;In the second period, we'll start revising Algebra.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-1032091275423604799?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/1032091275423604799/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=1032091275423604799' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1032091275423604799'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1032091275423604799'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/trigonometry.html' title='Trigonometry'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4194350902881093694</id><published>2008-04-01T13:00:00.000-07:00</published><updated>2008-11-12T21:09:27.829-08:00</updated><title type='text'>Arithmetic</title><content type='html'>If you work through all the part a,b and c type questions you got in class today and practice from previous exam papers, you'll be well prepared for Paper 1 Question 1.&lt;br /&gt;&lt;br /&gt;We went over 2 types of percentages problems in class:&lt;br /&gt;&lt;br /&gt;a) An item is reduced by 10% and the new price is 1125. What was the original price?&lt;br /&gt;&lt;br /&gt;and&lt;br /&gt;&lt;br /&gt;b) An amount is invested for 1 year at 6% interest rate and amounts to 5618 at the end of the year. What was the original principle invested?&lt;br /&gt;&lt;br /&gt;To answer both questions you need to look at the number you are given and work out what percentage this represents.&lt;br /&gt;&lt;br /&gt;In a) the amount 1125 represents 90%, so you can write down&lt;br /&gt;90% = 1125    &lt;- This is the most important step. Now I know 90%, I can work out what 10% is by dividing both sides by 9 10% = 125 100% = 1250  &lt;- 100% is the original amount before the reduction.  In b) the amount at the end of the year is the original principle (100%) plus 6% so you can write 106% = 5618 1% = 53   [dividing both sides by 106 to find what 1% is] 100% = 5300    &lt;- 100% is the original principle that was invested.&lt;br /&gt;&lt;br /&gt;In both cases the first step is key .. look at the number you are given and work out what percentage it represents. Then use the equation technique of multiplying or dividing on both sides of the equals by the same amount to find the percentage you are asked for.&lt;br /&gt;&lt;br /&gt;Here is the 1-page overview of arithmetic.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_Edu5_KEGUdY/R_KX7FUViRI/AAAAAAAAABU/H_2IHfC-x6M/s1600-h/p1q1.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://2.bp.blogspot.com/_Edu5_KEGUdY/R_KX7FUViRI/AAAAAAAAABU/H_2IHfC-x6M/s320/p1q1.gif" alt="" id="BLOGGER_PHOTO_ID_5184373162352412946" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Note that the formula for compound interest can be expressed in two ways.&lt;br /&gt;You can say&lt;br /&gt;&lt;br /&gt;1 + (Rate/100)&lt;br /&gt;&lt;br /&gt;or&lt;br /&gt;&lt;br /&gt;(100 + Rate)/100&lt;br /&gt;&lt;br /&gt;The key point is that if the rate is, say, 19%, then you will end up with&lt;br /&gt;Amount = Principle(1.19)^Years&lt;br /&gt;&lt;br /&gt;(Sorry about formatting , ^ means raised to a power)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4194350902881093694?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4194350902881093694/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4194350902881093694' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4194350902881093694'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4194350902881093694'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/04/arithmetic.html' title='Arithmetic'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_Edu5_KEGUdY/R_KX7FUViRI/AAAAAAAAABU/H_2IHfC-x6M/s72-c/p1q1.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6111753289722585720</id><published>2008-03-30T13:39:00.000-07:00</published><updated>2008-03-30T13:46:31.248-07:00</updated><title type='text'>One last day on co-ordinate geometry</title><content type='html'>In the last class before the break, we did a co-ordinate geometry test - with a Q2 and Q3 type question.&lt;br /&gt;Most people did well on Q2 (co-ordinate geometry of the line) but not well on Q3 (co-ordinate geometry of the circle).&lt;br /&gt;&lt;br /&gt;It is worth putting more work into this topic, especially the co-ordinate geometry of the circle as all you need to remember is&lt;br /&gt;&lt;ul&gt;&lt;li&gt;the formula of a circle&lt;span style="font-family:Arial, sans-serif;"&gt;&lt;i&gt;&lt;b&gt; (x-h)² + (y-k)² = r²&lt;/b&gt;&lt;/i&gt;&lt;/span&gt;  &lt;/li&gt;&lt;li&gt;all the co-ordinate geometry of the line you know so well anyway for Q2&lt;/li&gt;&lt;li&gt;the relationship between radius, diameter, tangents etc that you learned in Junior Cert&lt;/li&gt;&lt;li&gt;the intersection of a line &lt;a href="javascript:void(0)" tabindex="10" onclick="return false;"&gt;&lt;span&gt;&lt;/span&gt;&lt;/a&gt;and circle which you need to know anyway as it can come up in the algebra section of Paper 1.&lt;/li&gt;&lt;/ul&gt;We'll do a class covering overall approach to co-ordinate geometry on Monday, then move on.&lt;br /&gt;&lt;br /&gt;Don't forget that you are supposed to be attempting Leaving Cert 2003 over the Easter break.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6111753289722585720?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6111753289722585720/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6111753289722585720' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6111753289722585720'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6111753289722585720'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/03/one-last-day-on-co-ordinate-geometry.html' title='One last day on co-ordinate geometry'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2911376614342897026</id><published>2008-03-11T23:56:00.000-07:00</published><updated>2008-11-12T21:09:27.993-08:00</updated><title type='text'>Co-ordinate geometry</title><content type='html'>This topic is examined on Paper 2 question 2 and 3.&lt;br /&gt;Question 2 is co-ordinate geometry of the line only - this is mainly the same as Junior Cert Higher Level co-ordinate geometry, with the addition of finding the area of a triangle.&lt;br /&gt;Question 3 is co-ordinate geometry of the circle.&lt;br /&gt;Once you remember that the equation of a circle with centre (h,k) is  &lt;p style="margin-bottom: 0cm;"&gt;&lt;span style="font-family:Albany, sans-serif;"&gt;&lt;span style="font-size: 13pt;font-size:100%;" &gt;(x-h)² + (y-k)² = r²&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;and some basic rules about tangents to circles there is not a lot of extra work required for this question.&lt;br /&gt;&lt;br /&gt;Here is a 1-page overview.&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_Edu5_KEGUdY/R9d_GC-HdoI/AAAAAAAAABA/9n4SUUI95uQ/s1600-h/p2q2and3.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://1.bp.blogspot.com/_Edu5_KEGUdY/R9d_GC-HdoI/AAAAAAAAABA/9n4SUUI95uQ/s320/p2q2and3.gif" alt="" id="BLOGGER_PHOTO_ID_5176746038539024002" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2911376614342897026?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2911376614342897026/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2911376614342897026' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2911376614342897026'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2911376614342897026'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/03/co-ordinate-geometry.html' title='Co-ordinate geometry'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_Edu5_KEGUdY/R9d_GC-HdoI/AAAAAAAAABA/9n4SUUI95uQ/s72-c/p2q2and3.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4154096090578187845</id><published>2008-03-02T12:14:00.000-08:00</published><updated>2008-03-12T12:47:23.246-07:00</updated><title type='text'>Schedule of revision</title><content type='html'>This is what I propose for the next 8 weeks:&lt;br /&gt;&lt;table border="0" cellspacing="0" cols="3" frame="void" rules="none"&gt;  &lt;colgroup&gt;&lt;col width="49"&gt;&lt;col width="97"&gt;&lt;col width="323"&gt;&lt;/colgroup&gt;  &lt;tbody&gt;   &lt;tr&gt;    &lt;td align="right" height="18" valign="middle" width="49"&gt;&lt;b&gt;&lt;span style="font-size:78%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdnum="6153;0;DD/MMM" align="center" valign="middle" width="97"&gt;&lt;b&gt;Week starting&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="left" valign="middle" width="323"&gt;&lt;b&gt;Topics to be covered&lt;/b&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 1&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39510" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;03/Mar&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;3 classes complex numbers   /  2 classes probability / (1 class geometry on fri)&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 2&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39517" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;10/Mar&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;1 class probability / 4 classes co-ord geometry / 1 class arithmetic &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39524" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;17/Mar&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" bgcolor="#cccccc" valign="middle"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39531" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;24/Mar&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" bgcolor="#cccccc" valign="middle"&gt;&lt;br /&gt;&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 3&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39538" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;31/Mar&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;1 class arithmetic / 3 classes trigonometry / 1 class algebra&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 4&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39545" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;07/Apr&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;3 classes algebra / 2 classes functions + graphs&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 5&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39552" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;14/Apr&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;1 class functions + graphs / 4 classes differentiation&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 6&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39559" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;21/Apr&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;3 classes statistics / 2 classes linear programming&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 7&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39566" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;28/Apr&lt;/b&gt;&lt;/td&gt;    &lt;td style="border-style: solid; border-color: rgb(0, 0, 0); border-width: 1px 3px 1px 1px;" align="left" valign="middle"&gt;1 class linear programming / 3 classes perim, area + vol &lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;Week 8&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39573" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;05/May&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="left" valign="middle"&gt;General revision&lt;/td&gt;   &lt;/tr&gt;   &lt;tr&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="right" height="51" valign="middle"&gt;&lt;b&gt;&lt;i&gt;&lt;span style="font-size:78%;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/i&gt;&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" sdval="39580" sdnum="6153;0;DD/MMM" align="center" valign="middle"&gt;&lt;b&gt;12/May&lt;/b&gt;&lt;/td&gt;    &lt;td style="border: 1px solid rgb(0, 0, 0);" align="left" valign="middle"&gt;Graduation week&lt;/td&gt;   &lt;/tr&gt;  &lt;/tbody&gt; &lt;/table&gt;&lt;br /&gt;&lt;br /&gt;I haven't counted all 6 classes each week as there will inevitably be interruptions to classes due to oral exams etc so we can use those extra classes as contingency. I also haven't counted 2 days for reviewing the mock exams, since I don't know when they will be returned.&lt;br /&gt;If you feel strongly about re-ordering some of these topics, let me know.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4154096090578187845?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4154096090578187845/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4154096090578187845' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4154096090578187845'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4154096090578187845'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/03/schedule-of-revision.html' title='Schedule of revision'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2591580289520946291</id><published>2008-03-02T11:38:00.000-08:00</published><updated>2008-11-12T21:09:28.120-08:00</updated><title type='text'>Complex Numbers</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/R8sFrtfLpiI/AAAAAAAAAA4/OkbfcGmNQ8o/s1600-h/p1q4.gif"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/R8sFrtfLpiI/AAAAAAAAAA4/OkbfcGmNQ8o/s320/p1q4.gif" alt="" id="BLOGGER_PHOTO_ID_5173234845468042786" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;We will start Complex Numbers on Monday 3rd.&lt;br /&gt;Here is the 1 page overview:&lt;br /&gt;&lt;br /&gt;As with every topic we will be doing over the next 8 weeks, some of you need to work on this topic from scratch while others just need practice.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2591580289520946291?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2591580289520946291/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2591580289520946291' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2591580289520946291'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2591580289520946291'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/03/complex-numbers.html' title='Complex Numbers'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/R8sFrtfLpiI/AAAAAAAAAA4/OkbfcGmNQ8o/s72-c/p1q4.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2690584719227068781</id><published>2008-03-02T11:35:00.001-08:00</published><updated>2008-03-02T11:38:32.477-08:00</updated><title type='text'>Geometry overview</title><content type='html'>We discussed the approach to geometry in Friday's class.&lt;br /&gt;Study the theorems one by one at home. &lt;br /&gt;In class, we covered the basics you need for Section A, Q4: essentially JC higher level geometry and the concept of enlargement. &lt;br /&gt;On Friday 7th during the 2nd maths period, we'll take a look at the Section B, Q8.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2690584719227068781?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2690584719227068781/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2690584719227068781' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2690584719227068781'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2690584719227068781'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/03/geometry-overview.html' title='Geometry overview'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-1632668812380912557</id><published>2008-02-27T14:28:00.000-08:00</published><updated>2008-02-27T14:40:11.316-08:00</updated><title type='text'>Geometry revisited</title><content type='html'>Since quite a few students are interested in geometry, I've looked into whether we can cover this section of the course in the time remaining.&lt;br /&gt;Basically, if you know your theorems from higher level junior cert and remember the basics of geometry, you should have few problems with LC ordinary level geometry.&lt;br /&gt;We won't have time to go through each theorem individually, but they should be easy to study on your own. The geometry questions (4 and 8) usually have a part b which involves proving a theorem. &lt;br /&gt;We will do the constructions and enlargements in class. &lt;br /&gt;If your preference was to stick with the questions and options we have already covered, don't worry. We will spend just a few classes on geometry and you can work on other maths material during those classes.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-1632668812380912557?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/1632668812380912557/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=1632668812380912557' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1632668812380912557'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/1632668812380912557'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/geometry-revisited.html' title='Geometry revisited'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-558677524675688865</id><published>2008-02-26T12:24:00.000-08:00</published><updated>2008-02-26T12:42:10.979-08:00</updated><title type='text'>After the mocks ...</title><content type='html'>With the mock exams completed, we have to settle on a schedule of revision.&lt;br /&gt;Not including 2 weeks at Easter and the week starting May 12th, we will have 8 weeks of normal class time, give or take a day here or there.&lt;br /&gt;&lt;br /&gt;We are currently prepared for the following.&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight:bold;"&gt;Paper 1: &lt;/span&gt;&lt;br /&gt;Q 1,2,3,4,6,7,8 (must do 6 of these 7 questions)&lt;br /&gt;We left out Q5 &lt;span style="font-style:italic;"&gt;Sequences and Series&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style="font-weight:bold;"&gt;Paper 2: &lt;/span&gt;&lt;br /&gt;Section A Q 1,2,3,5,6,7 (must do 5 of these 6 questions)&lt;br /&gt;We left out Q4 &lt;span style="font-style:italic;"&gt;Theorems and Enlargements&lt;/span&gt;.&lt;br /&gt;Section B Q 11 (must do 1, there are 3 other options)&lt;br /&gt;We left out Q8 &lt;span style="font-style:italic;"&gt;Further Geometry&lt;/span&gt;, Q9 &lt;span style="font-style:italic;"&gt;Vectors &lt;/span&gt;and Q10 &lt;span style="font-style:italic;"&gt;Further Sequences and Series&lt;/span&gt;.&lt;br /&gt;&lt;br /&gt;Do we want to prepare for any further questions?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-558677524675688865?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/558677524675688865/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=558677524675688865' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/558677524675688865'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/558677524675688865'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/after-mocks.html' title='After the mocks ...'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-8481238306824917086</id><published>2008-02-07T14:08:00.000-08:00</published><updated>2008-11-12T21:09:29.110-08:00</updated><title type='text'>Linear Programming</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uCbq-bIOI/AAAAAAAAAAw/W8S5WyZu0YM/s1600-h/p2q11.gif"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uCbq-bIOI/AAAAAAAAAAw/W8S5WyZu0YM/s320/p2q11.gif" border="0" alt=""id="BLOGGER_PHOTO_ID_5164364809614598370" /&gt;&lt;/a&gt;&lt;br /&gt;The other topic we will cover in Friday's class is Linear Programming.&lt;br /&gt;You need to know all the inequalities, simultaneous equations and co-ordinate geometry stuff for other parts of the paper anyway, so Linear Programming gives you an extra question with very little extra work.&lt;br /&gt;It is the only option in Section B which we will be doing for now.&lt;br /&gt;This is the 1-pager.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-8481238306824917086?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/8481238306824917086/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=8481238306824917086' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8481238306824917086'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/8481238306824917086'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/linear-programming.html' title='Linear Programming'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uCbq-bIOI/AAAAAAAAAAw/W8S5WyZu0YM/s72-c/p2q11.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6580480241844696611</id><published>2008-02-07T14:04:00.000-08:00</published><updated>2008-11-12T21:09:29.313-08:00</updated><title type='text'>Perimeter, Area + Volume</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uBSq-bINI/AAAAAAAAAAo/LAOVxXBcMzY/s1600-h/p2q1.gif"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uBSq-bINI/AAAAAAAAAAo/LAOVxXBcMzY/s320/p2q1.gif" border="0" alt=""id="BLOGGER_PHOTO_ID_5164363555484147922" /&gt;&lt;/a&gt;&lt;br /&gt;Here is my 1-page overview of what you need to know.&lt;br /&gt;Practice using the formulae for surface area, volume etc as they are presented in the mathematical tables.&lt;br /&gt;Simpson's rule is in the tables also, but not in the form we are used to. h/3(1st+last+TOFE) is a good way to remember it, but you have to practice.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6580480241844696611?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6580480241844696611/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6580480241844696611' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6580480241844696611'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6580480241844696611'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/perimeter-area-volume.html' title='Perimeter, Area + Volume'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/R6uBSq-bINI/AAAAAAAAAAo/LAOVxXBcMzY/s72-c/p2q1.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-7956781380323161855</id><published>2008-02-07T03:43:00.000-08:00</published><updated>2008-06-04T12:42:00.125-07:00</updated><title type='text'>Alegbra class</title><content type='html'>Last night's homework question 2 had a simultaneous equation - one linear one quadratic - type question. Notethat it was xy and not x², but it has to be handled the same way.&lt;br /&gt;x + 3 = 2y&lt;br /&gt;xy – 7y + 8 = 0 &amp;lt;-this is the quadratic (can be x² or xy)&lt;br /&gt;x = 2y -3                 [rearrange linear equation]&lt;br /&gt;(2y-3)(y) – 7y + 8 = 0    [sub in new value for x]&lt;br /&gt;2y² – 3y -7y +8 = 0&lt;br /&gt;2y² – 10y + 8 = 0         [always simplify equation if you can]&lt;br /&gt;y² -5y + 4 = 0            [factor -4 x -1 = 4 and -4 -1 = -5]&lt;br /&gt;(y-1)(y-4) = 0&lt;br /&gt;So y = 1,4&lt;br /&gt;If y= 1 then&lt;br /&gt;x = 2(1) – 3, so x = -1     values: x = -1, y = 1&lt;br /&gt;if y= 4 then&lt;br /&gt;x = 2(4) – 3, so x = 5      values: x = 5, y = 4&lt;br /&gt;And &lt;span style="font-weight: bold;"&gt;always check&lt;/span&gt;:&lt;br /&gt;(-1)(1) – 7(1) + 8 = 0             &lt;br /&gt;(5)(4) – 7(4) + 8 = 0&lt;br /&gt;&lt;br /&gt;Part c of this question works out as follows:&lt;br /&gt;(i) &lt;u&gt;√x&lt;/u&gt; +&lt;u&gt; 1 &lt;/u&gt;[Turn them into same type of fraction ... LCM of 1 and √x is √x]&lt;br /&gt;              1      √x&lt;br /&gt;=&lt;u&gt; √x√x&lt;/u&gt; + &lt;u&gt;1 &lt;/u&gt;[multiply above and below leftmost fraction by √x]&lt;br /&gt;√x √x&lt;br /&gt;= &lt;u&gt;x + 1&lt;/u&gt; [don't forget √x√x = x]&lt;br /&gt;√x&lt;br /&gt;&lt;br /&gt;ii) ( &lt;u&gt;2√x&lt;/u&gt; ) • (&lt;u&gt;x + 1 )&lt;/u&gt; [cancel (x + 1) with (1+x) and cancel √x with 2√x ]&lt;br /&gt;(1+x ) ( √x )&lt;br /&gt;= 2&lt;br /&gt;&lt;br /&gt;iii) 2 = x -3&lt;br /&gt;x = 5&lt;br /&gt;&lt;br /&gt;Tomorrow's double class will be Perimeter area + volume (1st period) and Linear Programming (2nd period) - Homework for tomorrow is &lt;a href="http://www.examinations.ie/archive/exampapers/2006/LC003GLP200EV.pdf"&gt;2006 Paper 2&lt;/a&gt; - q1 and 11.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-7956781380323161855?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/7956781380323161855/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=7956781380323161855' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7956781380323161855'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/7956781380323161855'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/alegbra-class.html' title='Alegbra class'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-4467366252457471418</id><published>2008-02-06T09:35:00.000-08:00</published><updated>2008-11-12T21:09:29.599-08:00</updated><title type='text'>Leaving Cert Algebra</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_Edu5_KEGUdY/R6nwJa-bIMI/AAAAAAAAAAg/6pO8kMGlySo/s1600-h/p1q2and3.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://4.bp.blogspot.com/_Edu5_KEGUdY/R6nwJa-bIMI/AAAAAAAAAAg/6pO8kMGlySo/s320/p1q2and3.gif" alt="" id="BLOGGER_PHOTO_ID_5163922492407619778" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;There are two algebra questions on Paper 1 and algebra permeates almost every question on the exam to a certain extent. It is worthwhile investing time and effort in practising algebra.&lt;br /&gt;&lt;br /&gt;This is my 1-page overview of algebra - an outline of the basic concepts you need to master.&lt;br /&gt;We will review this in Thursday's class.&lt;br /&gt;&lt;br /&gt;Homework for Thursday is &lt;a href="http://www.examinations.ie/archive/exampapers/2005/LC003GLP100EV.pdf"&gt;2005 Paper 1&lt;/a&gt; questions 2 and 3.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-4467366252457471418?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/4467366252457471418/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=4467366252457471418' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4467366252457471418'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/4467366252457471418'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/leaving-cert-algebra.html' title='Leaving Cert Algebra'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_Edu5_KEGUdY/R6nwJa-bIMI/AAAAAAAAAAg/6pO8kMGlySo/s72-c/p1q2and3.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-2919152465845213382</id><published>2008-02-06T08:21:00.000-08:00</published><updated>2008-02-06T08:35:55.939-08:00</updated><title type='text'>Statistics wrap-up</title><content type='html'>For the most part the statistics homework was well done.&lt;br /&gt;It was question 7 on &lt;a href="http://www.examinations.ie/archive/exampapers/2006/LC003GLP200EV.pdf"&gt;this paper.&lt;/a&gt;&lt;br /&gt;The two difficulties seemed to be&lt;br /&gt;&lt;ul&gt;&lt;li&gt;creating the cumulative frequency table from the original data given. Make sure that the last number in the cumulative frequency table is the sum of all the frequencies - which was 80 (already used this value in part ii)&lt;/li&gt;&lt;li&gt;figuring out how many cars were priced between the mean and the median. This was an unusual question. You had to take the mean you calculated in part ii (26.25 or 26,250), find this value on the X-axis, trace a vertical line to the curve and then find the corresponding position on the Y-axis. This should be 50. That tells you that the "50th car" is priced at the mean price. The number between the mean and median is therefore 50-40= 10 cars.&lt;/li&gt;&lt;/ul&gt;Note with this question that the mean would be quite a bit higher than the median. Why do you think this is?&lt;br /&gt;&lt;br /&gt;Thursday's class will be all algebra.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-2919152465845213382?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/2919152465845213382/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=2919152465845213382' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2919152465845213382'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/2919152465845213382'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/statistics-wrap-up.html' title='Statistics wrap-up'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6096380658799434027</id><published>2008-02-05T12:47:00.000-08:00</published><updated>2008-02-05T12:59:26.316-08:00</updated><title type='text'>Statistics again</title><content type='html'>Today's class didn't go to plan - too many students didn't do the weekend work and we didn't get through the corrections.&lt;br /&gt;We will have to do a full revision of Statistics in tomorrow's class and set the homework on Algebra.&lt;br /&gt;Homework for the evening of 6th Feb will be two algebra questions: the 2005 paper I, q2 and q3.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6096380658799434027?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6096380658799434027/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6096380658799434027' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6096380658799434027'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6096380658799434027'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/statistics-again.html' title='Statistics again'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-6237182081284101646</id><published>2008-02-04T14:05:00.000-08:00</published><updated>2008-11-12T21:09:29.734-08:00</updated><title type='text'>Leaving Cert Statistics</title><content type='html'>There are lies, damned lies and statistics - attributed to Mark Twain or Disraeli depending on how you google it.&lt;br /&gt;Statistics is the art of interpreting data - summarising complex data in numbers (by calculating a mean or a standard deviation) or presenting it graphically in graphs.&lt;br /&gt;If you understand statistics, you'll know when someone is using their statistical knowledge to warp and twist the truth for their own advantage ... if you master statistics, you'll be able to warp and twist the truth to your own advantage.&lt;br /&gt;&lt;br /&gt;We'll revise Statistics in class on Feb 5th.&lt;br /&gt;Homework will be LC 2006 Paper 2 Q 7&lt;br /&gt;Here is my 1 pager&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6ePNq-bILI/AAAAAAAAAAM/myAMTLZCxVo/s1600-h/p2q7.gif"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer;" src="http://3.bp.blogspot.com/_Edu5_KEGUdY/R6ePNq-bILI/AAAAAAAAAAM/myAMTLZCxVo/s320/p2q7.gif" alt="" id="BLOGGER_PHOTO_ID_5163252962840748210" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-6237182081284101646?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/6237182081284101646/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=6237182081284101646' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6237182081284101646'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/6237182081284101646'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/leaving-cert-statistics.html' title='Leaving Cert Statistics'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_Edu5_KEGUdY/R6ePNq-bILI/AAAAAAAAAAM/myAMTLZCxVo/s72-c/p2q7.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5129052553947207130.post-5358221384042150568</id><published>2008-02-04T12:51:00.000-08:00</published><updated>2008-02-06T09:45:05.155-08:00</updated><title type='text'>Introduction</title><content type='html'>This blog is aimed at my Leaving Cert students who are taking Ordinary Level Maths gearing up for their Mock exams and then for the Leaving Cert exams in June.&lt;br /&gt;&lt;br /&gt;In real-world class, we will be preparing for the Mock exams which take place during the week starting Feb 18th.&lt;br /&gt;&lt;br /&gt;Students can keep up with the schedule of revision using this blog. Any other students who may find this blog useful are welcome to join in.&lt;br /&gt;&lt;br /&gt;The questions we are working toward are as follows:&lt;br /&gt;Paper I&lt;br /&gt;   Q1    Arithmetic (completed mid Jan)&lt;br /&gt;   Q2    Algebra (Thurs 7th Feb)&lt;br /&gt;   Q3    Algebra (..)&lt;br /&gt;   Q4    Complex Numbers (Thurs 31 Jan)&lt;br /&gt;   Q6    Functions (Fri 1 and Tue 5 Feb)&lt;br /&gt;   Q7    Calculus   (Fri 1 and Tue 5 Feb)&lt;br /&gt;   Q8    Calculus   (Fri 1 and Tue 5 Feb)&lt;br /&gt;Paper II&lt;br /&gt;   Q1    Perimeter Area + Volume (Fri 8 Feb)&lt;br /&gt;   Q2    Co-ord geom of Line (Fri 25 Jan)&lt;br /&gt;   Q3    Co-ord geom of Circle (Mon 28 Jan)&lt;br /&gt;   Q5    Trigonometry (Tue 29 Jan)&lt;br /&gt;   Q6    Probability (Wed 30 Jan)&lt;br /&gt;   Q7    Statistics (Wed 6 Feb)&lt;br /&gt;   Q11    Linear Programming (Fri 8 Feb)&lt;br /&gt; &lt;br /&gt;All your comments and constructive feedback are welcome!&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5129052553947207130-5358221384042150568?l=leavingcertmaths.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://leavingcertmaths.blogspot.com/feeds/5358221384042150568/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5129052553947207130&amp;postID=5358221384042150568' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5358221384042150568'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5129052553947207130/posts/default/5358221384042150568'/><link rel='alternate' type='text/html' href='http://leavingcertmaths.blogspot.com/2008/02/first-post.html' title='Introduction'/><author><name>Maths Teacher</name><uri>http://www.blogger.com/profile/04931561575939838832</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry></feed>
